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Karo-lina-s [1.5K]
2 years ago
9

A coordinate plane linear graph shows inequalities. A line goes through (0, 1) and (2, minus 1). Another line goes through (0, m

inus 3) and (2, 1). From intersection, region to the right of it is A, below is D, to the left is C, and above is B. The region in the graph that represents the solution of the system of linear inequalities y ≥ 2x − 3 and y ≤ -x + 1 is .
Mathematics
1 answer:
Alborosie2 years ago
6 0

The region in the graph that represents the solution of the system of linear inequalities y ≥ 2x − 3 and y ≤ -x + 1 is given by C region , This can be clearly understood from the graph attached.

<h3>What is Inequality ?</h3>

When two algebraic expressions are equated by an inequality operator then the mathematical statement formed is called inequality

It is given that a line passes through the points  (0, 1) and (2, minus 1)

The equation of the line representing this is given by

y = mx+c

m = -1

y = -x+1

and the other line passing through the points of (0, minus 3) and (2, 1) is

m = 2

y = 2x -3

These are plotted on the graph

From intersection, region to the right of it is A, below is D, to the left is C, and above is B.

These are noted ion the graph

Then the inequalities are plotted y ≥ 2x − 3 and y ≤ -x + 1

The region in the graph that represents the solution of the system of linear inequalities y ≥ 2x − 3 and y ≤ -x + 1 is given by C region , This can be clearly understood from the graph.

To know more about Inequality

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AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

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Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

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(a) What is the probability that a drought lasts exactly 3 intervals?

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f(x) = (1-p)^{x}p

f(3) = (1-0.383)^{3}*(0.383)

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At most 3 intervals?

This is P = f(0) + f(1) + f(2) + f(3)

f(x) = (1-p)^{x}p

f(0) = (1-0.383)^{0}*(0.383) = 0.383

f(1) = (1-0.383)^{1}*(0.383) = 0.236

f(2) = (1-0.383)^{2}*(0.383) = 0.146

Previously in this exercise, we found that f(3) = 0.09

So

P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4).

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

P(X \leq 3) + P(X \geq 4) = 1

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