Answer:
Step-by-step explanation:
Combine like terms
3v + 4v
26=7v+12
Subtract 12 from both sides of the equation
26-12
12-12
14=7v
Simplify
so subtract the 12's
Divide both sides of the equation by the same term
14 divided by 7
7 divided by 7
Simplify
do the division and move the term on the other side and it would be
v=2
Solution
v=2
Answer:
a) 25.15
b)
x = 1
y = t
z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)
c) (x,y) = (1, -2pi)
Step-by-step explanation:
a)
First lets calculate the velocity, that is, the derivative of c(t) with respect to t:
v(t) = (-sin(t), cos(t), 2t)
The velocity at t0=4pi is:
v(4pi) = (0, 1, 8pi)
And the speed will be:
s(4pi) = √(0^2+1^2+ (8pi)^2) = 25.15
b)
The tangent line to c(t) at t0 = 4pi has the parametric form:
(x,y,z) = c(4pi) + t*v(4pi)
Since
c(4pi) = (1, 0, (4pi)^2)
The tangent curve has the following components:
x = 1
y = t
z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)
c)
The intersection with the xy plane will occurr when z = 0
This happens at:
t1 = -2pi
Therefore, the intersection will occur at:
(x,y) = (1, -2pi)
Answer:
a, y =3/x
x = 0.5 => y = 3/0.5 = 6
x = 1 => y = 3/1 = 3
x = 2 => y = 3/2 = 1.5
x = 3 => y = 3/3 = 1
x = 4 => y = 3/4 = 0.75
b,
y = 3/x passes (0.5, 6) => A is correct
Hope this helps!
D,A,B,C i think this is correct !
