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svp [43]
3 years ago
6

The equation of line q is y = 1/3x-7Parallel to line q is liner, which passes through the

Mathematics
1 answer:
grigory [225]3 years ago
7 0

Answer:

y =  \frac{1}{3} x - 10

Step-by-step explanation:

The equation of a line is usually written in the form of y=mx+c, where m is the gradient and c is the y-intercept.

Parallel lines have the same gradient. Hence the gradient of line r is \frac{1}{3}.

Susbt. m=\frac{1}{3},

y =  \frac{1}{3} x + c

To find c, substitute a coordinate.

When x=3, y= -9,

- 9 =  \frac{1}{3} (3) + c

-9= 1 +c

c= -9-1

c= -10

Thus the equation of line r is y =  \frac{1}{3} x - 10.

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What is the solution to the problem 2y+3=4y+2
yulyashka [42]

Answer:

y = 1/2

Step-by-step explanation:

<u>Step 1:  Solve for y</u>

2y + 3 = 4y + 2

2y + 3 - 2 - 2y = 4y + 2 - 2 - 2y

1 / 2 = 2y / 2

1/2 = y

Answer:  y = 1/2

8 0
2 years ago
Read 2 more answers
The value of y varies directly with x and y = 4.5 when x = 0.5. find y when x = 10
Pepsi [2]
So what you asked this is what I got

x(y) = 4.5

If x= 0.5 then 

0.5(y) = 4.5
y=9

x(y) = 4.5

10(y) = 4.5
y= 0.45



hope this helps :)





3 0
3 years ago
A worker at a snack stand opened a new box of cups. On the first day, the worker used 30 cups from the box. On the second day, t
Solnce55 [7]

Answer:

<em>630 cups</em>

Step-by-step explanation:

<u>Percentages</u>

This problem is most easily solved backward, i.e., from the final data up to the beginning.

There was a new box of cups and the worker at a snack stand opened it. He first used 30 cups from the box and the second day he uses 15% of the remaining cups in the box, and we are told that represents 90 cups.

If 15% (0.15) equals 90 cups, then the number of cups before the second day was 90/0.15 = 600 cups.

On the first day, we used 30 cups, thus the original number of cups in the box was 600+30=630 cups

7 0
2 years ago
What are the first three terms of the Arithmetic Sequence an=11-3(n-1)?
svlad2 [7]

Answer:

11,8,5

Step-by-step explanation:

an=11-3(n-1)

Let n=1

a1 = 11 - 3(1-1)

    = 11 -0

    =11

Let n=2

a2 = 11-3(2-1)

     = 11 -3(1)

     = 8

Let n=3

a3 = 11-3(3-1)

    = 11 -3(2)

    = 11 -6

    =5

5 0
3 years ago
PLEASE DON’T ANSWER IF YOU DONT KNOW THE ANSWER!!!
Blababa [14]
D should be correct because you add all the boxes that’s inside the rectangle
3 0
3 years ago
Read 2 more answers
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