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Sophie [7]
3 years ago
7

Explain to me all the steps to find slope of the line

Mathematics
1 answer:
MrRissso [65]3 years ago
3 0

Step-by-step explanation:

The slope of a line characterizes the direction of a line. To find the slope, you divide the difference of the y-coordinates of 2 points on a line by the difference of the x-coordinates of those same 2 points .

Let me know of this helps!

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If the smallest angle of a triangle is 20 degrees and it is included between sides of 4 and 7, then (to the nearest tenth) the s
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Al 'Kashi theorem says:

a²=4²+7²-2*4*7*cos 20°=12.37721...
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Given a right triangle with sides a = 3 , b = 4, and c = 5. Find the missing side c of another right triangle with a = 6 and b =
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<em>c = 10</em>

Step-by-step explanation:

We can find out the missing side of a right triangle by using the Pythagorean theorem.

The Pythagorean theorem is...

a^2+b^2=c^2

We can even double check the first problem by plugging in everything into the theorem and solving, everything will come out correct. We can plug in the numbers from the second problem into the theorem and find c, also please note that the hypotenuse of a triangle will <em>always </em>be c. It doesn't matter which you put in for a or b, but since the problem gives us which one is a and which one is b, I'll just be plugging it in like that.

6^2+8^2=c^2

36+64=c^2

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<em><u>c = 10</u></em>

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3 years ago
Read the passage from "Annabel Lee.”
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6 0
3 years ago
Find the standard equation of a sphere that has diameter with the end points given below. (3,-2,4) (7,12,4)
DiKsa [7]

Answer:

The standard equation of the sphere is (x-5)^{2} + (y-5)^{2} + (z-4)^{2}  = 53

Step-by-step explanation:

From the question, the end point are (3,-2,4) and (7,12,4)

Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.

The midpoint can be calculated thus

Midpoint = (\frac{x_{1} + x_{2}  }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2}  }{2})

Let the first endpoint be represented as (x_{1}, y_{1}, z_{1}) and the second endpoint be (x_{2}, y_{2}, z_{2}).

Hence,

Midpoint = (\frac{x_{1} + x_{2}  }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2}  }{2})

Midpoint = (\frac{3 + 7  }{2}, \frac{-2+12 }{2}, \frac{4 + 4  }{2})

Midpoint = (\frac{10 }{2}, \frac{10}{2}, \frac{8  }{2})\\

Midpoint = (5, 5, 4)

This is the center of the sphere.

Now, we will determine the distance (diameter) of the sphere

The distance is given by

d = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} + (z_{2}- z_{1})^{2}      }

d = \sqrt{(7 - 3)^{2} +(12 - -2)^{2} + (4- 4)^{2}

d = \sqrt{(4)^{2} +(14)^{2} + (0)^{2}

d = \sqrt{16 +196 + 0

d =\sqrt{212}

d = 2\sqrt{53}

This is the diameter

To find the radius, r

From Radius = \frac{Diameter}{2}

Radius = \frac{2\sqrt{53} }{2}

∴ Radius = \sqrt{53}

r = \sqrt{53}

Now, we can write the standard equation of the sphere since we know the center and the radius

Center of the sphere is (5, 5, 4)

Radius of the sphere is \sqrt{53}

The equation of a sphere of radius r and center (h,k,l) is given by

(x-h)^{2} + (y-k)^{2} + (z-l)^{2}  = r^{2}

Hence, the equation of the sphere of radius \sqrt{53} and center (5, 5, 4) is

(x-5)^{2} + (y-5)^{2} + (z-4)^{2}  = \sqrt{(53} )^{2}

(x-5)^{2} + (y-5)^{2} + (z-4)^{2}  = 53

This is the standard equation of the sphere

6 0
3 years ago
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