Stance formula : d = sqrt (x2 - x1)^2 + (y2 - y1)^2
(3,5)(7,3)
d = sqrt (7 - 3)^2 + (3 - 5)^2
d = sqrt 4^2 + (-2^2)
d = sqrt 16 + 4
d = sqrt 20
d = 4.47....rounded = 4.5
Answer:
Step-by-step explanation:
(x) = (1100 + x) (100 - .05(x-1100))
This is a quadratic, graphs as a parabola that opens downward. A maximum cam be found.
The zeros of the function are
(1100 + x) = 0 ..... or ..... [100 - .05(x-1100)] = 0
x = -1100 is the left x-intercept.
[100 - .05(x-1100)] = 0
100 = .05(x-1100)
2000 = x - 1100
x = 3100 is the right intercept.
Maximization of profits is at the mid point of the zeros (x-intercepts)
(3100 + -1100)/2 = 1000
1100 + 1000 = 2100 trees should be planted to maximize profits.
f(x) = (1100 + 1000) (100 - .05(1000-1100))
f(x) = (2000) (105) = 220,500 is the maximum profit.
I hope this helps!
1 mile is equal to 5280 feet
Add 900 to it:
5280 + 900 = 6180
6180 is less than 6200, so 1 mile and 900 feet is less than 6200 feet.
We know that m ║ n.
Let's first find the value 'x'.
When two lines are parallel, and a transversal is drawn, the angles on the same side of the transversal are equivalent.
This means that (5x + 16)° and (7x + 4)° are equivalent.
Equating them,
5x + 16 = 7x + 4
16 - 4 = 7x - 5x
12 = 2x
x = 12/2
x = 6°
Since we know the value of 'x', let's substitute them into the angles and find out the actual measurements.
5x + 16 = 5 × 6 + 16 = 30 + 16 = 46°.
7x + 4 = 7 × 6 + 4 = 42 + 4 = 46°.
Now let's find the value of 'y'.
If you observe carefully, (7x + 4)° and (y + 6)° form a linear pair.
This means that both those angles should add upto 180°.
Using that theory, the following equation can be framed:
(y + 6)°+ (7x + 4)° = 180°
Since we know the actual value of (7x + 4)°, let's substitute that value and move ahead.
(y + 6)° + 46° = 180°
y + 6 + 46° = 180
y + 52° = 180°
y = 180° - 52°
y = 128°
Therefore, the values of 'x' and 'y' are 46° and 128° respectively.
Hope it helps. :)
Answer:
These two figures are similar because 
equals 
Step-by-step explanation:
The figures will be similar if their ratios of the two sides are equal. So we need to check the ratios of the figures to see if they are similar or not.
For the smaller figure the ratio is , and for the bigger figure the ratio is which upon simplification reduces to .
So we see that the ratios are equal. Thus the figures are similar.
