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4 years ago

1. Ron makes $1,659 a month. What is the maximum monthly rent he can afford?

2 answers:

3 0

Here are my notes for monthly rents:

Landlords typically require that your annual income is at least 40 times the monthly rent. For example, if you and your roommate are looking at a $3,000 per month apartment, the landlord would require a combined income of $3,000 × 40, which equals $120,000. To determine how much rent you (and your potential roommates) can afford, simply divide your combined annual incomes by 40.

I hope my guide has come to your help. God bless and have a nice day ahead!

anygoal [31]4 years ago

3 0

Hello there.

1. Ron makes $1,659 a month. What is the maximum monthly rent he can afford?

$414.75

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A student believes that the average grade on the statistics final examination was 87. A sample of 36 final examinations was take

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Answer:

The p-value for this test is 0.1375.

Step-by-step explanation:

A student believes that the average grade on the statistics final examination was 87. The student wants to test whether the average is different from 87 at 90% level of confidence.

At the null hypothesis, we test if the average is 87, that is:

$H_0: \mu = 87$

At the alternate hypothesis, we test if the average is different from 87, that is:

$H_a: \mu \neq 87$

The test statistic is:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $s$ is the standard deviation of the sample and n is the size of the sample.

87 is tested at the null hypothesis:

This means that $\mu = 87$

The average grade in the sample was 83.96 with a standard deviation of 12. Sample of 36

This means that $X = 83.96, s = 12, n = 36$

Value of the test-statistic:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{83.96 - 87}{\frac{12}{\sqrt{36}}}$

$t = -1.52$

Pvalue:

Probability of the sample mean differing of 87, which means that we have a two-tailed test, with t = -1.52 and 36 - 1 = 35 degrees of freedom.

With the help of a calculator, the pvalue is of 0.1375.

The p-value for this test is 0.1375.

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Answer:

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