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3 years ago

5 points

Mathematics

1 answer:

jek_recluse [69]3 years ago

4 0

Answer:

(0, 5000)

The value of the account at the start of the year is 5000

Step-by-step explanation:

Given the equation that represents the value, y, of one account that was left inactive for a period of x years as;

y = 5000(0.98)^x

The y-intercept of the equation occurs at x = 0

Substitute x = 0 into the expression

y = 5000(0.98)^0

y = 5000(1) (any value raise to power of zero is 1)

y = 5000

Hence the y intercept is (0, 5000)

This means that the value of the account at the start of the year is 5000

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Otrada [13]

Answer:

What?

Step-by-step explanation:

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2 years ago

Suppose the average math SAT score for students enrolled at local community college is 490.4 with a standard deviation of 63.7.

lakkis [162]

Answer:

Option B) 9.1

Step-by-step explanation:

We are given the following in the question:

Average score = 490.4

Standard deviation = 63.7

Sample size, n = 49

Formula:

$=\dfrac{\sigma}{\sqrt{n}}$

Putting values, we get,

Standard error =

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Thus, the correct answer is

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8 0

2 years ago

App 19.study

lions [1.4K]

Answer:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

Step-by-step explanation:

Given

$n = 125$

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

$Pr = \frac{Frequency}{n}$

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

$Pr(2) = \frac{13}{125} = 0.104$

$Pr(4) = \frac{29}{125} = 0.232$

$Pr(6) = \frac{6}{125} = 0.048$

When the frequency is to be calculated, we use:

$Pr = \frac{Frequency}{n}$

$Frequency = n * Pr$

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

$Frequency(3) = 125 * 0.144 = 18$

$Frequency(5) = 125 * 0.296 = 37$

For roll of 1 where the frequency and the probability are not known, we use:

$Total \ Frequency = 125$

So:

Frequency(1) added to others must equal 125

This gives:

$Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125$

$Frequency(1) + 103 = 125$

Collect like terms

$Frequency(1) =- 103 + 125$

$Frequency(1) =22$

The probability is then calculated as:

$Pr(1) = \frac{22}{125}$

$Pr(1) = 0.176$

So, the complete table is:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

5 0

2 years ago

-7p+2(5p-8)=6(p+6)-7

-BARSIC- [3]

Answer:

-15

Step-by-step explanation:

-7p+10p-16=6p+36-7

3p-16=6p+29

3p-6p=29+16

-3p=45

p=45/-3

p=-15

5 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP <br> What is the sum of the first 7 terms of the series: -8 + 16 - 36 + 64 -...?

mr Goodwill [35]

-12

-8+16-36+64-112+188-124

6 0

2 years ago