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3 years ago

5 points

Mathematics

1 answer:

jek_recluse [69]3 years ago

4 0

Answer:

(0, 5000)

The value of the account at the start of the year is 5000

Step-by-step explanation:

Given the equation that represents the value, y, of one account that was left inactive for a period of x years as;

y = 5000(0.98)^x

The y-intercept of the equation occurs at x = 0

Substitute x = 0 into the expression

y = 5000(0.98)^0

y = 5000(1) (any value raise to power of zero is 1)

y = 5000

Hence the y intercept is (0, 5000)

This means that the value of the account at the start of the year is 5000

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