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xxMikexx [17]
3 years ago
5

Consider the series 7/9+7/27+7/81+1/243 Which expression defines Sn?

Mathematics
2 answers:
Fed [463]3 years ago
6 0

Answer:

It’s d

Step-by-step explanation:

Shtirlitz [24]3 years ago
3 0

Answer:

b or c

Step-by-step explanation:

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(1/3)y2 + 12 = 5x where x = 3
IgorLugansk [536]
If x=3
(1/3)y2+12=15
(1/3)y2=15-12
(1/3)y2=3
y2=3*3
y2=9
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8 0
3 years ago
1+4x=29 what does x =1+4x=29 what does x =
AlladinOne [14]

Answer:

Step-by-step explanation:

1+4x=29

-1 -1

4x=28

4x/4=28/4

X=7

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3 years ago
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A recipe calls for 1/2 cup of milk for 4 servings. If we want to make 6 servings, how much milk will we need?
ExtremeBDS [4]
Answer is: 0.75(3/4)
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3 years ago
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A set of data is normally distributed with a mean of 327 and a standard deviation of 27.
d1i1m1o1n [39]

Answer:

  86.7%

Step-by-step explanation:

For questions regarding values related to a normal distribution, a suitable calculator is required. Numerous calculators, apps, web sites, and spreadsheets are capable of answering this question.

__

One standard deviation above the mean is 327 +27 = 354, so the value is expected to be slightly more than 50% +34% = 84%. It is no surprise, then, that a calculator tells you 86.7% of the data is below 857.

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<em>Additional comment</em>

The "empirical rule" tells you 68% of the area is within 1 standard deviation of the mean. The distribution is symmetrical, so half that, 34%, is between the mean and 1 standard deviation above the mean. Of course, 50% of the data is below the mean.

5 0
2 years ago
SCALCET8 3.9.017.MI. Two cars start moving from the same point. One travels south at 48 mi/h and the other travels west at 20 mi
Veronika [31]

Answer:

The rate at which the distance between the cars increasing two hours later=52mi/h

Step-by-step explanation:

Let

Speed of one car, x'=48 mi/h

Speed of other car, y'=20 mi/h

We have to find the rate at which the distance between the cars increasing two hours later.

After 2 hours,

Distance traveled by one car

x=48\times 2=96 mi

Using the formula

Distance=Time\times speed

Distance traveled by other car

y=20\times 2=40 mi

Let z be the distance between two cars after 2 hours later

z=\sqrt{x^2+y^2}

Substitute the values

z=\sqrt{(96)^2+(40)^2}

z=104 mi

Now,

z^2=x^2+y^2

Differentiate w.r.t t

2z\frac{dz}{dt}=2x\frac{dx}{dt}+2y\frac{dy}{dt}

z\frac{dz}{dt}=x\frac{dx}{dt}+y\frac{dy}{dt}

Substitute the values

104\frac{dz}{dt}=96\times 48+40\times 20

\frac{dz}{dt}=\frac{96\times 48+40\times 20}{104}

\frac{dz}{dt}=52mi/h

Hence, the rate at which the distance between the cars increasing two hours later=52mi/h

3 0
3 years ago
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