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Vlad1618 [11]
3 years ago
8

Need help 20-24 anything helps

Mathematics
1 answer:
BartSMP [9]3 years ago
8 0
I’ve attached the work done on the paper
Hope this helped!

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Which sequences of transformations performed on rhombus ABCD shows its congruency to rhombus A'B'C'D?
Veronika [31]

Answer:

a 90° clockwise rotation about the origin and then a reflection a cross the x-axis

4 0
3 years ago
The play will be negative 12 degrees tonight, the weatherman predicts it will be 25 degrees warmer by noon tomorrow, what was th
Vsevolod [243]

the temperature differential is based on the numbers on a line with the negative numbers left of zero and the positive numbers right of zero.

 

Using -12 on the number line, add 25 to it to get the noon temperature tomorrow.

 

Awnser -12 + 25 = 13

 

The temperature tomorrow at noon will be 13 degrees.

 

Questions?

3 0
4 years ago
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Question 4 of 25
yanalaym [24]

Answer:

true

Step-by-step explanation:

5 0
3 years ago
After an extensive advertising campaign, the manager of a company expects the proportion of potential customers that recognize a
lina2011 [118]

Answer:

Step-by-step explanation:

Hello!

The study variable is:

X: number of customers that recognize a new product out of 120.

There are two possible recordable outcomes for this variable, the customer can either "recognize the new product" or " don't recognize the new product". The number of trials is fixed, assuming that each customer is independent of the others and the probability of success is the same for all customers, p= 0.6, then we can say this variable has a binomial distribution.

The sample proportion obtained is:

p'= 54/120= 0.45

Considering that the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample proportion to normal: p' ≈ N(p;\sqrt{\frac{p(1-p)}{n} })

The other conditions for this approximation are also met: (n*p)≥5 and (n*q)≥5

The probability of getting the calculated sample proportion, or lower is:

P(X≤0.45)= P(Z≤\frac{0.45-0.6}{\sqrt{\frac{0.6*0.4}{120} } })= P(Z≤-3.35)= 0.000

This type of problem is for the sample proportion.

I hope this helps!

5 0
3 years ago
John's sister went shopping with him. She expected to spend $100 on clothes, but spent only $10. John wanted to help her calcula
Taya2010 [7]

Answer:

10%

Step-by-step explanation:

8 0
3 years ago
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