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4 years ago

Please help me! Don't answer if you do not know

Mathematics

1 answer:

emmainna [20.7K]4 years ago

4 0

What is the question ?

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Please help the question is in the picture.

jeyben [28]

Because thee dimensions of ΔRAH is twice as large as corresponding dimensions of ΔEAC,

|RA|=2|EA|=2*3.5=7

|AH|=2|AC|=2*6=12

So, we have that 2 corresponding sides are in proportion and angle between them =90⁰, so the angle between them are congruent,

we can use SAS to prove that these triangles are similar.

4 0

4 years ago

Round 28,928 to the nearest thousand

klio [65]

The answer will be 29,000

5 0

3 years ago

Sin(A+B) sin(A-B) /sin^A Cos^B=1-cot^A Tan^B

telo118 [61]

In order to prove

$\dfrac{\sin(x+y)\sin(x-y)}{\sin^2(x)\cos^2(x)}=1-\cot^2(x)\tan^2(y)$

Let's write both sides in terms of $\sin(x),\ \sin^2(x),\ \cos(x),\ \cos^2(x)$ only.

Let's start with the left hand side: we can use the formula for sum and subtraction of the sine to write

$\sin(x+y)=\cos(y)\sin(x)+\cos(x)\sin(y)$

and

$\sin(x-y)=\cos(y)\sin(x)-\cos(x)\sin(y)$

So, their multiplication is

$\sin(x+y)\sin(x-y)=(\cos(y)\sin(x))^2-(\cos(x)\sin(y))^2\\=\cos^2(y)\sin^2(x)-\cos^2(x)\sin^2(y)$

So, the left hand side simplifies to

$\dfrac{\cos^2(y)\sin^2(x)-\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}$

Now, on with the right hand side. We have

$1-\cot^2(x)\tan^2(y)=1-\dfrac{\cos^2(x)}{\sin^2(x)}\cdot\dfrac{\sin^2(y)}{\cos^2(y)} = 1-\dfrac{\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}$

Now simply make this expression one fraction:

$1-\dfrac{\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}=\dfrac{\sin^2(x)\cos^2(y)-\cos^2(x)\sin^2(y)}{\sin^2(x)\cos^2(y)}$

And as you can see, the two sides are equal.

6 0

4 years ago

find the perimeter of the quadrilateral, 31 + (4x^2+8x) + (3x^2-5x+20) + (7x+30). if x=2, what is the perimeter

Westkost [7]

31 + (4*2^2 + 8*2) + (3*2^2 + 5*2 + 20) + (7*2 + 30) = 129

4 0

3 years ago

Which of the following is the solution to the equation 3 over 4y = 24?

Sophie [7]

3/4 y= 24

Multiply both sides of the equation by 4/3 (the reciprocal of 3/4) to be left with y.

4/3 × 3/4y = 24 × 4/3

y = 24 × 4/3

y = 32

Hope this helps!

5 0

3 years ago

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