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Aleks04 [339]
3 years ago
11

Mary Grace has 3 more Jolly Ranchers than Isabella. If Isabella has 10 Jolly Ranchers, how many do they have total?

Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
5 0

Answer:23

Step-by-step explanation:

10+3=13 so that means that mary has 13 and isabella has 10

Then if you add 13+10=23

so they have 23 jolly ranchers in all.

weeeeeb [17]3 years ago
3 0
23 i think because 10 + 3 = 13 and 13 + 10 = 22
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Akimi4 [234]

Answer:

415.96yds sq

Step-by-step explanation:

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SA of the squares=(8*8)*2=128

SA of the rectangles=(10*8)*3=240

SA of the semicircles= 3.14*r*r=3.14*4*4=3.14*16=50.24

SA of half the cylinder= (2*3.14*r*h)/2= (2*3.14*4*10)/2=(3.14*80)/2=251.2/2=125.6

Now you add them all together

128+240+50.24+125.6=415.96

and you add units

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3 years ago
PLS HELP WILL MARK BRAINIEST!!!! TY
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Step-by-step explanation:

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PLEADE HELP ILL GIVE BRAINLIST QUESTION IN PHOTO
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x = 3

Step-by-step explanation:

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3 years ago
2х5y-3z-=14<br> x-2y+=-12<br> -x+ Зу-2z =13
lukranit [14]

Answer:

x = -34/3, y = 1/3, and z = -35/3

Step-by-step explanation:

2х+5y-3z-=14   <u>let's call this </u><u>equation 1.</u>

x-2y=-12   <u>let's call this </u><u>equation 2.</u>

-x+Зу-2z =13  <u>let's call this </u><u>equation 3.</u>

<u>USING </u><u>EQUATION 1</u><u> AND </u><u>EQUATION 3</u><u>.</u>

2х+5y-3z-=14   (EQUATION 1)

-x+Зу-2z =13  (EQUATION 3)

<u>LET'S GET RID OF </u><u>z</u><u>, BY MAKING THE COEFFICIENT OF </u><u>z</u><u> IN THE TWO EQUATION THE SAME. WE WILL MULTIPLY </u><u>EQUATION 1</u><u> BY </u><u>2</u><u> AND </u><u>EQUATION 3</u><u> BY </u><u>3</u><u>.</u>

2х+5y-3z-=14   (EQUATION 1) * 2

-x+Зу-2z =13  (EQUATION 3) * 3

4х+10y-6z-=28   <u>let's call this </u><u>equation 4.</u>

-3x+9у-6z =39  <u>let's call this </u><u>equation 5.</u>

<u>TO GET RID OF </u><u>z</u><u>, WE WILL HAVE TO SUBTRACT </u><u>EQUATION 5</u><u> FROM </u><u>EQUATION 4</u><u> PLEASE TAKE NOTE OF THE SIGNS (-) (+).</u>

4х+10y-6z-=28   (EQUATION 4)

- (-3x+9у-6z =39) (EQUATION 5)

(4x - 3x) + ((+10y) - (+9y)) + ((-6z) - (-6z)) = (28 - 39)

x + y + 0 = -11

x + y = -11  <u>let's call this </u><u>equation 6.</u>

<u>USING </u><u>EQUATION 2</u><u> AND </u><u>EQUATION 6</u><u>, LET'S FIND </u><u>x</u><u> AND </u><u>y</u><u>.</u>

x-2y=-12  (EQUATION 2)

x + y = -11  (EQUATION 6)

<u>x</u><u> has the same coefficient in both equations, which is </u><u>1</u><u>. Let's get rid of </u><u>x</u><u> so we can find the value of </u><u>y</u><u>.</u>

<u>We will subtract </u><u>equation 6</u><u> from </u><u>equation 2</u><u>. Take note of the signs.</u>

x-2y=-12  (EQUATION 2)

- (x + y = -11)  (EQUATION 6)

(x - x) + ((-2y) - (+y)) = ((-12) - (-11))

0 + -3y = -1

-3y = -1

<u>Divide both sides by </u><u>-3</u><u>.</u>

-3y/-3 = -1/-3

y = 1/3

<u>LET'S SUBSTITUTE THE VALUE OF </u><u>y</u><u> INTO</u><u> EQUATION 2</u><u> TO GET THE VALUE OF </u><u>x</u><u>.</u>

x-2y=-12  (EQUATION 2)

x-2(1/3)=-12  

x -2/3 = -12

<u>Add </u><u>2/3</u><u> to both sides.</u>

x -2/3 + (2/3) = -12 + (2/3)

x + 0 = -34/3

x = -34/3

<u>LET'S SUBSTITUTE THE VALUES OF </u><u>x</u><u> and </u><u>y</u><u> INTO</u><u> EQUATION 1</u><u> TO GET THE VALUE OF </u><u>z</u><u>.</u>

2х+5y-3z-=14   (EQUATION 1)

2(-34/3)+5(1/3)-3z-=14  

-68/3 + 5/3 - 3z = 14

-21 - 3z = 14

<u>Add </u><u>21</u><u> to both sides.</u>

-21 + (21) - 3z = 14 + (21)

0 - 3z = 35

-3z = 35

<u>Divide both sides by </u><u>-3</u><u>.</u>

-3z/-3 = 35/-3

z = -35/3 <em>or</em>  

Therefore, x = -34/3, y = 1/3, and z = -35/3

Please thank, rate 5 stars, and give brainliest. Thank you.

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3 years ago
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