Answer:
The probability of getting exactly two read marbles is P = 0,003456%
Step-by-step explanation:
So, each of the following sequences are the desired results(I will use R for a red marble and G for a green marble).
S(1) = R-R-G-G
S(2) = R-G-R-G
S(3) = R-G-G-R
S(4) = G-R-R-G
S(5) = G-R-G-R
S(6) = G-G-R-R
In all, considering there are replacement, there can be 10*10*10*10 = 10000 total sequences, so the probability of getting exactly two read marbles is
P = \frac{P(S(1)) + P(S(2)) + P(S(3)) + P(S(4)) + P(S(5)) + P(S(6))}{10000}
where
P(S(1)) = P(S(2)) = P(S(3)) = P(S(4)) = P(S(5)) = P(S(6)) = (0.4)^{2}*(0.6)^{2} = 0.16*0.36 = 0.0576.
The probability of getting exactly two read marbles is
P = \frac{6*0.0576}{10000} = 0,003456%
<span>According to the Exterior Angle Theorem, the</span> measure of an exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles of the triangle.
11x+2=5x+10 + 58
6x=66
x=11
A is the best option it results in 69.9
