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3 years ago

12

If a kitten weighted 2 pounds 3 ounces. A month later the kitten weighted 56 ounces. How much weight did the kitten gain in that

month?

1 answer:

True [87]3 years ago

5 0

Answer:

21 ounces

Step-by-step explanation:

You might be interested in

Find the measure of angle TUV

denpristay [2]

Answer:

∠TUV = 120°

Step-by-step explanation:

Since this figure is a kite, we know that; ∠TUV ≈ ∠TWV, so first we solve for x:

9x - 6 = 7x + 22

2x - 6 = 22

2x = 28

x = 14

Now, substitute 14 in for x, in the equation for ∠TUV:

∠TUV = 9x - 6

∠TUV = 9(14) - 6

∠TUV = 126 - 6

∠TUV = 120°

Hope this helps!

4 0

3 years ago

Find the value of x. O is the center of the circle. Round your answer to the nearest hundredth.

katrin [286]

$x=5.38$ . Correct option C)5.38

<u>Step-by-step explanation:</u>

Here we have , Find the value of x. O is the center of the circle. Round your answer to the nearest hundredth. picture is attached . Let's find out:

In the given figure , Let's draw a line from center to the point where cord of length 8 unit is touching the circle or intersecting or , where this chord finishes . This line is radius of circle and is denoted by x , So now we have a right angle triangle with dimensions as :

$Perpendicular =3.6\\Base=\frac{8}{2}=4\\Hypotenuse=x$

By Pythagoras Theorem ,

$Hypotenuse^2=Perpendicular^2+base^2$

⇒ $x^2=(3.6)^2+(4)^2$

⇒ $x=\sqrt{(3.6)^2+(4)^2}$

⇒ $x=\sqrt{12.96+16}$

⇒ $x=\sqrt{28.96}$

⇒ $x=5.38$

Therefore , $x=5.38$ . Correct option C)5.38

6 0

3 years ago

What is the equation for a geometric sequence with a first term of 2 and second term of -8?

Naya [18.7K]

A(1) = 2
r = a(2)/a(1) = -8/2 = -4

$a(n) =a {(r)}^{n - 1} \\ a(n) = 2 {( - 4)}^{n - 1}$
Answer will be D.

!! Hope It Helps !!

4 0

3 years ago

A student carried out an experiment to determine the amount of vitamin C in a tablet sample. He performed 5 trials to produce th

ivolga24 [154]

Answer:

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

P-value = 0.166.

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{5}(490+502+505+495+492)\\\\\\M=\dfrac{2484}{5}\\\\\\M=496.8\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{4}((490-496.8)^2+(502-496.8)^2+(505-496.8)^2+(495-496.8)^2+(492-496.8)^2)}\\\\\\s=\sqrt{\dfrac{166.8}{4}}\\\\\\s=\sqrt{41.7}=6.5\\\\\\$

Then, we can perform the hypothesis t-test for the mean.

The claim is that the amount of vitamin C in a tablet sample is different from 500 mg.

Then, the null and alternative hypothesis are:

$H_0: \mu=500\\\\H_a:\mu< 500$

The significance level is 0.05.

The sample has a size n=5.

The sample mean is M=496.8.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=6.5.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{6.5}{\sqrt{5}}=2.907$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{496.8-500}{2.907}=\dfrac{-3.2}{2.907}=-1.1$

The degrees of freedom for this sample size are:

$df=n-1=5-1=4$

This test is a left-tailed test, with 4 degrees of freedom and t=-1.1, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=P(t$

As the P-value (0.166) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

4 0

3 years ago

Ling our 1500 in a savings account the simple interest rate is 1.5% how much simple interest will he earn after three years

natima [27]

Answer:

Step-by multiply 1500 × 0.015 × 36 to get that:

The interest is: $810.00

4 0

3 years ago