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Nataly_w [17]
2 years ago
10

Find f(x) and g(x) so the function can be expressed as y = f(g(x)). y =2/x^(2) + 3

Mathematics
2 answers:
professor190 [17]2 years ago
5 0

One <em><u>possible answer</u></em> is:

f(x) = (2/x) + 3 and g(x) = x².

Explanation:

We are to write this equation as y = f(g(x)).  This means we want it to be a composite of functions; in f(x), we take the value of g(x) and use in place of x.

If we let g(x) = x², this means everywhere we see an x in f(x), we will replace it with x².  To make our equation y = 2/x² + 3, working backward we would substitute x for x²; this would give us f(x) = 2/x + 3.

LuckyWell [14K]2 years ago
4 0

We are asked to find f(x) and g(x) so the function can be expressed as y = f(g(x) such that y = y =2/x^(2) + 3. There are many possibilities here but we go to the simplest ones. we can have g (x) = x2 and f(x) is equal to 2/x + 3. 
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Answer:

c Point E

Step-by-step explanation:

Remember coplanar means being on the same plane.

Look at each side/square as a plane. If we look closely, we can see that A, C, G, and E are on the same square/plane. E is coplanar.

6 0
3 years ago
1.Explain how you can use the distributive property to check the binomial factors when a trinomial has been factored. Include an
sdas [7]
The question is asking to state on how to use the distributive property to check the binomial factor when a trinomial has been factored. In my calculation and further research, I would say that the answer would be that you have to split one of the binomial and then apply the distributive property. 
7 0
3 years ago
Please help me Please this is due today
Tasya [4]

Answer:

See Below.

Step-by-step explanation:

By the Factor Theorem, if we divide <em>q(x)</em> into <em>p(x) </em>and the resulting remainder is 0, then <em>p(x)</em> is divisible by <em>q(x)</em> (i.e. there are no remainders).

Problem 1)

We are given:

p(x)=x^3+3x^2+3x+1\text{ and } q(x)=x+1

We should find the remainder when dividing <em>p(x)</em> and <em>q(x)</em>. We can use the Polynomial Remainder Theorem. When dividing a polynomial <em>p(x)</em> by a binomial in the form of (<em>x</em> - <em>a</em>), then the remainder will be <em>p(a).</em>

Here, our divisor is (<em>x</em> + 1) or (<em>x</em> - (-1)). So, <em>a </em>= -1.

Then by the Polynomial Remainder Theorem, the remainder when performing <em>p(x)/q(x)</em> is:

p(-1)=(-1)^3+3(-1)^2+3(-1)+1=0

The remainder is 0, satisfying the Factor Theorem. <em>p(x)</em> is indeed divisible by <em>q(x)</em>.

Problem 2)

We are given:

p(x)=x^3-2x^2+6x-27\text{ and } q(x)=x-3

Again, use the PRT. In this case, <em>a</em> = 3. So:

p(3)=(3)^3-2(3)^2+6(3)-27=0

It satisfies the Factor Theorem.

Problem 3)

We are given:

p(x)=x^n-10^n\text{ and } q(x)=x-10

Use the PRT. In this case, <em>a</em> = 10. So:

p(10)=(10)^n-10^n=0

It satisfies the Factor Theorem.

Since all three cases satisfy the Factor Theorem, <em>p(x)</em> is divisible by <em>q(x)</em> in all three instances.

7 0
2 years ago
Use the substitution method for solve for x and y.<br><br><br> y = 2x + 10<br> y = -4x - 2
Sever21 [200]
Hereeeeee x = -2 , y = 6
4 0
3 years ago
3-7, rounded to the nearest hundredth of a percent
tangare [24]

Answer:

3/7≈42.86%

Step-by-step explanation:

To get to a percent from a fraction, multiply the fraction by 100 then divide.

3/7*100=300/7≈42.86

3 0
3 years ago
Read 2 more answers
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