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zalisa [80]
2 years ago
15

Use a flowchart to prove if the triangles in each pair of similar. NO LINKS!!!​

Mathematics
2 answers:
vekshin12 years ago
7 0

Answer:

Step-by-step explanation:

Start

<F = <Q                     Given

<GPF = <RPQ           Vertically opposite angles

<FGP = <QRP            A triangle has 180 degrees. 2 equal angles means the third pair must be equal

Triangle GPF ~ Triangle RPQ   AAA

end

I don't see any way to make these triangles similar except by stating the statement and why it is so. There really are no yes / no choices. If you get another answer, choose it.

20

JL/LE = 90/27                 Given

KL /LD = 90/27               Given

<JLK = <DLK                   Vertically opposite

Are the ratios equal       Yes  Then is the angle included Yes

Then the triangles are similar.

Are the ratios not equal  No then the triangles cannot be similar

Is the angle not included  Then similarity cannot be proved.

ΔJLK ≈ ΔDLK                  Equal Ratios and included angle === similarity

VMariaS [17]2 years ago
4 0

9514 1404 393

Explanation:

19) ∠F ≅ ∠Q; ∠FPG ≅ ∠QPR  ⇒  ∆FPG ~ ∆QPR (AA)

__

20) LE/LK = 3/10; ∠ELD ≅ ∠KLJ; LD/LJ = 3/10*  ⇒  ∆ELD ~ ∆KLJ (SAS)

* the ratios are the same, hence the sides are proportional

_____

The above format A; B; C ⇒ (similarity statement) (postulate) is intended to be sufficient for you to fill in a flowchart diagram similar to the one attached.

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3 years ago
Read 2 more answers
What are the solutions to the equation 3x2 + 3x +7 = 0?​
KATRIN_1 [288]

Answer:

x is equal to 0.94 and -1.94

Step-by-step explanation:

3x² + 3x + 7 = 0

9x² + 9x + 21 = 0

9x² + 9x + 2.25 = 18.75

(3x + 1.5)² = 18.75

3x + 1.5 = ±√18.75

3x = -1.5  ±√18.75

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7 0
3 years ago
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In your own words what is the definition of reflection (in geometry)
sergeinik [125]

Answer:

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Step-by-step explanation:

7 0
2 years ago
A farmer has 520 feet of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one s
Setler [38]

Answer:

310\text{ feet and }210\text{ feet}

Step-by-step explanation:

GIVEN: A farmer has 520 \text{ feet} of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one side of the pen. The length of the barn is 310 \text{ feet}.

TO FIND: Determine the dimensions of the rectangle of maximum area that can be enclosed under these conditions.

SOLUTION:

Let the length of rectangle be x and y

perimeter of rectangular pen =2(x+y)=520\text{ feet}

                                                x+y=260

                                               y=260-x

area of rectangular pen =\text{length}\times\text{width}

                                       =xy

putting value of y

=x(260-x)

=260x-x^2

to maximize \frac{d \text{(area)}}{dx}=0

260-2x=0

x=130\text{ feet}

y=390\text{ feet}

but the dimensions must be lesser or equal to than that of barn.

therefore maximum length rectangular pen =310\text{ feet}

                              width of rectangular pen =210\text{ feet}

Maximum area of rectangular pen =310\times210=65100\text{ feet}^2

Hence maximum area of rectangular pen is 65100\text{ feet}^2 and dimensions are 310\text{ feet and }210\text{ feet}

5 0
3 years ago
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