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zalisa [80]
3 years ago
15

Use a flowchart to prove if the triangles in each pair of similar. NO LINKS!!!​

Mathematics
2 answers:
vekshin13 years ago
7 0

Answer:

Step-by-step explanation:

Start

<F = <Q                     Given

<GPF = <RPQ           Vertically opposite angles

<FGP = <QRP            A triangle has 180 degrees. 2 equal angles means the third pair must be equal

Triangle GPF ~ Triangle RPQ   AAA

end

I don't see any way to make these triangles similar except by stating the statement and why it is so. There really are no yes / no choices. If you get another answer, choose it.

20

JL/LE = 90/27                 Given

KL /LD = 90/27               Given

<JLK = <DLK                   Vertically opposite

Are the ratios equal       Yes  Then is the angle included Yes

Then the triangles are similar.

Are the ratios not equal  No then the triangles cannot be similar

Is the angle not included  Then similarity cannot be proved.

ΔJLK ≈ ΔDLK                  Equal Ratios and included angle === similarity

VMariaS [17]3 years ago
4 0

9514 1404 393

Explanation:

19) ∠F ≅ ∠Q; ∠FPG ≅ ∠QPR  ⇒  ∆FPG ~ ∆QPR (AA)

__

20) LE/LK = 3/10; ∠ELD ≅ ∠KLJ; LD/LJ = 3/10*  ⇒  ∆ELD ~ ∆KLJ (SAS)

* the ratios are the same, hence the sides are proportional

_____

The above format A; B; C ⇒ (similarity statement) (postulate) is intended to be sufficient for you to fill in a flowchart diagram similar to the one attached.

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4 0
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a wire of length 200 cm is cut into two parts and each part is bent to form a square.If the area of the larger square is 9 times
diamong [38]

<em>Answer:</em>

<em>The perimeter of the larger square is 150cm.</em>

<em>Step-by-step explanation:</em>

<em>First of all, let one part of it be "x"</em>

<em>and the other part of it "200-x"</em>

<em>Now to solve this :</em>

<em>The area of the square = L^2</em>

<em>The area of one part of the square = x^2</em>

<em>The area of the other part of the square = (200-x)^2</em>

<em>9x^2= (200-x)^2\\9x^2=40000-400x+x^2</em>

<em></em>

<em>Now, add, -4x^2 to both the sides :</em>

<em>9x^2-9x^2=40000-400x+x^2-9x^2\\-1(8x^2+400x-40000)=0</em>

<em />

<em>Now, take out the "8" which is common :</em>

<em>-8(x^2+50x-5000)=0</em>

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<em>Now, divide it by -8 :</em>

<em>x^2+100x-50x-5000=0\\x(x+100)-50(x+100)=0\\(x+100)(x-50)=0\\</em>

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<em />

<em>So, now we know that :</em>

<em>One of the part is = 50cm</em>

<em>And the other part is = 150cm</em>

<em />

<em>Thus the perimeter of the larger square is = 150cm</em>

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KATRIN_1 [288]

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Step-by-step explanation:

Side by side on the left ,side by side on the right and two in the middle

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