All categories

4 years ago

If point A is between B and C then BA + AC = BC. always sometimes never

Mathematics

2 answers:

Art [367]4 years ago

6 0

The answer is Always

Step-by-step explanation:

koban [17]4 years ago

3 0

Always

Anytime point A is on line BC, AB+BC=BC

You might be interested in

What is n (AUB) if (A)=25,n(B) = 10 and BCA<br>

Maru [420]

Answer:

Step-by-step explanation:

It is in the above photo .

7 0

3 years ago

A car travels at 45 miles per hour how long did it travel in 4 hours?

wolverine [178]

Answer:

180 miles

Step-by-step explanation:

just multiple 45X4

7 0

3 years ago

Use the minimum and maximum data entries and the number of classes to find the class width, the lower class limits, and the uppe

deff fn [24]

Answer:

The class width is $C_w \approx 13$

Step-by-step explanation:

From the question we are told that

The upper class limits is $max = 121$

The lower class limits is $min = 14$

The number of classes is $n = 8 \ classes$

The class width is mathematically represented as

$C_w = \frac{max - min}{n }$

substituting values

$C_w = \frac{121 - 14}{8 }$

$C_w = 13.38$

$C_w \approx 13$

Since

5 0

3 years ago

Can anyone help me with the answer to this please?

stiks02 [169]

Answer:

Step-by-step explanation:

To find the inverse function switch variables out and solve for y

y=(x+3)/x swap variables to get

(y+3)/y=x then solve for y

y+3=yx

y-yx+3=0

y-yx=-3

y(1-x)=-3

y=-3/(1-x)

y=3/(x-1)

8 0

3 years ago

In a relay race, the probability of the Galaxy team winning is 22%. In another unrelated relay race, the probability of the Kome

Shalnov [3]

Answer: There is probability of approximately 12% that Komets losing their race and the Galaxy winning their game.

Explanation:

Since we have given that

Probability of the Galaxy team wins = 22%

Probability of the Komets team wins = 47%

So, Probability of the Komets losing their race is given by

$100-47=53\%$

We need to find the probability of the Komets losing their and the Galaxy winning their game .

Let Event K : Komets losing their game

Event G : Galaxy winning their game

Since these are two independent events,

So,

$P(K\cap G)=P(K).P(G)\\\\P(K\cap G)=0.22\times 0.53\\\\P(K\cap G)=0.1166=0.12=12\%$

So, there is probability of 12% that Komets losing their race and the Galaxy winning their game.

3 0

3 years ago

Read 2 more answers