So we have to start at 3.5 up the y axis. Then, we have to move 3 slots to the right. Let me know if this helps!
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Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
3^3+14*y-(25*y-13)-(y+7*y-9*y)=0
Equation at the end of step 1
((3³ + 14y) - (25y - 13)) - -y = 0
Pull out like factors :
40 - 10y = -10 • (y - 4)
Equation at the end of step3:
-10 • (y - 4) = 0
STEP4:
Equations which are never true:
Solve : -10 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation:
Solve : y-4 = 0
Add 4 to both sides of the equation :
y = 4
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7. y=-3/2x+8 (3rd answer choice)
substitute
-4=-3/2(8)+b
-4=-24/2 +b
-4=-12+b
+12 both sides
8=b
so equation would be...
y=-3/2x+8 (3rd answer choice)
8. y=-5x-17 (2nd answer choice)
substitute
-2=-5(-3)+b
-2=15+b
-15 both sides
-17=b
so the equation would be...
y=-5x-17 (2nd answer choice)
check your work by substituting each (x,y) value into the final equations if you want. hope this helps :))
Oh okay I’m not going home I’m sorry I don’t have to sleep tueitu lol I
Answer:
It will take the boulder approximately 4.28 seconds to hit the road
Step-by-step explanation:
The given height of the cliff from which the boulder falls, h = 90 feet
The equation that can be used to find the time it takes the boulder to fall is h = u·t + (1/2)·g·t²
Where;
h = The height of the cliff = 90 ft.
u = The initial velocity of the boulder = 0 m/s (The boulder is assumed to be at rest when it falls)
g - The acceleration due to gravity ≈ 9.81 m/s²
t = How long it will take for the boulder to hit the road below
Plugging in the values gives;
90 = 0 × t + (1/2)×9.81×t² = 4.905·t²
∴ t = √(90/4.905) ≈ 4.28
The time it takes the boulder to hit the road, t ≈ 4.28 seconds.
