Help please 3 + 3 + 2 x 2 x 1 = ?

A runner ran at a steady rate, stopped to retie their shoes, and then ran at a steady rate again, this time slower than they ran

daser333 [38]

The First Graph represents the situation.
The runner goes a lot of distance in a short amount of time (Demonstrated by the steep incline of the first portion). When the runner is tying their shoe, the distance remains the same, thus eliminating the second graph and the last graph because the last graph doesn't show the beginning of the problem. Finally, we know that the runner is slower after tying their shoe, this means the incline of the line would be far less as steep (Meaning the slope would be smaller). The only graph that depicts all of these, is the first one.

I Hope this Helps!
-Sinnamin

5 0

4 years ago

Read 2 more answers

What is the derivative of 1/square root 4x.

Bumek [7]

Answer:

$\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4x^\bigg{\frac{3}{2}}}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Exponential Properties

Exponential Property [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Property [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

Identify.

$\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg]$

Step 2: Differentiate

Simplify: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \bigg( \frac{1}{2\sqrt{x}} \bigg)'$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{1}{\sqrt{x}} \bigg)'$
Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{1}{x^\Big{\frac{1}{2}}} \bigg)'$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( x^\bigg{\frac{-1}{2}} \bigg)'$
Derivative Rule [Basic Power Rule]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{1}{2} \bigg( \frac{-1}{2} x^\bigg{\frac{-3}{2}} \bigg)$
Simplify: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4} x^\bigg{\frac{-3}{2}}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle \frac{d}{dx} \bigg[ \frac{1}{\sqrt{4x}} \bigg] = \frac{-1}{4x^\bigg{\frac{3}{2}}}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

5 0

3 years ago

A store is having a sale all items are marked 30% off

zepelin [54]

Since you didn’t put the numbers to find the amount, I’ll teach you how to.. Once you have the decimal figure, multiply it by the number for which you seek to calculate the percentage

6 0

3 years ago

The sum of two numbers is 68 and the difference is 12. What are the numbers? Larger number: Smaller number:

Lady_Fox [76]

Answer:

This is hard asfk

Step-by-step explanation:

Sorry but im confused just as you.

5 0

3 years ago

R , S, and T are the vertices of one triangle. E, F, and D are the vertices of another triangle. mR = 60, mS = 80, mF = 60, mD =

Mumz [18]

Answer:

Yes, the two triangles are congruent, by ASA.

Step-by-step explanation:

In order to find if two triangles are congruent, you need the information of at least three out of the six incongnits of a triangle (the incognits are the three sides and the three angles)

Some of the ways to know if they're congruents are:

-ASA (Angle, side, angle): Two angles and the included side are equal for both triangles.

-AAS(Angle, angle, side): Two angles and a non-incuded side are equal for both triangles

-SAS(Side, angle, side): Two sides and the included angle are equal for both triangles.

In this case, two angles and one side of each triangle are known.

For the triangle RST, you know two angles and the included side.

For the triangle EFD, you know two angles and the non-included side. But is also known that the sum of the angles of a triangle is 180°, therefore you can obtain the third angle of EFD:

180=m∡F+m∡D+m∡E

m∡E= 180 - 60 -40

m∡E= 80°

Therefore:

m∡E=m∡S

m∡F=m∡R

RS=EF

Hence, two angles and the included side for RST and EFD are equal and the triangles are congruent by ASA.

8 0

3 years ago