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adelina 88 [10]
3 years ago
8

Which of the following fractions compares BC to BD? coordinate plane with segment BD at B 0 comma 1 and D 5 comma 1; point C is

on segment BD and 2 comma 1 two thirds five halves two fifths three halves
Mathematics
1 answer:
Liula [17]3 years ago
5 0

Answer:

2/5

Step-by-step explanation:

The distance between two points A(u, v) and B(x,y) is given by the equation:

AB=\sqrt{(y-v)^2+(x-u)^2}

Since point B is at (0, 1), point D is at (5, 1) and point C is at (2, 1)

Therefore the distance between BC and BD is:

BC=\sqrt{(1-1)^2+(2-0)^2}=\sqrt{4} = 2\\  BD=\sqrt{(1-1)^2+(5-0)^2}=\sqrt{25} = 5

The ratio between two lines is gotten by dividing their distances by each other.

The ratio of BC to BD is:

Ratio\ of\ BC\ to \ BD=\frac{BC}{BD}=\frac{2}{5}

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\rm\displaystyle  0,\pm\pi

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===========================

we want to find all possible values of α+β+γ when <u>tanα+tanβ+tanγ = tanαtanβtanγ</u><u> </u>to do so we can use algebra and trigonometric skills first

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\rm\displaystyle   \tan( \gamma ) =   -  \tan( t)

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