Question

Which of the following fractions compares BC to BD? coordinate plane with segment BD at B 0 comma 1 and D 5 comma 1; point C is on segment BD and 2 comma 1 two thirds five halves two fifths three halves

Answer 1

Answer:

2/5

Step-by-step explanation:

The distance between two points A(u, v) and B(x,y) is given by the equation:

$AB=\sqrt{(y-v)^2+(x-u)^2}$

Since point B is at (0, 1), point D is at (5, 1) and point C is at (2, 1)

Therefore the distance between BC and BD is:

$BC=\sqrt{(1-1)^2+(2-0)^2}=\sqrt{4} = 2\\ BD=\sqrt{(1-1)^2+(5-0)^2}=\sqrt{25} = 5$

The ratio between two lines is gotten by dividing their distances by each other.

The ratio of BC to BD is:

$Ratio\ of\ BC\ to \ BD=\frac{BC}{BD}=\frac{2}{5}$