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pav-90 [236]
3 years ago
15

Can someone pleasee help

Mathematics
1 answer:
katrin2010 [14]3 years ago
6 0

Answer:

y-intercept: (0, 5)

Step-by-step explanation:

This parabola has an equation of -x² + 4x + 5.

It's y-intercept is (0, 5).

It's x-intercepts or roots are (-1, 0) and (5, 0).

It's vertex is (2, 9).

___________________________________

Keep in mind that the y-intercept is when x = 0.

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3 years ago
Read 2 more answers
What are the approximate values of the minimum and maximum points of f(x) = x5 − 10x3 + 9x on [-3,3]?
nika2105 [10]

Answer:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.

Step-by-step explanation:

Given:

f(x)=x^5-10x^3+9x; [-3,3]

Explanation:

In order to find minimum/maximum of a function, we need to find the first derivative of the function and then set it equal to 0 to get critical points.

Therefore,

f'(x)=5x^4-30x^2+9

Setting derivative equal to 0, we get

5x^4-30x^2+9=0

On applying quadratic formula, we get

x=2.4, -2.4, -0.7, 0.7.

So, those are critical points of the given function.

Plugging the values x=2.4, -2.4, -0.7, 0.7, -3 and 3 in above function, we get

f(2.4)=(2.4)^5-10(2.4)^3+9(2.4)= -37.01376   : Minimum.

f(-2.4)=(-2.4)^5-10(-2.4)^3+9(-2.4)= 37.01376 : Maximum.

f(0.7)=(0.7)^5-10(0.7)^3+9(0.7) = 3.03807

f(-0.7)=(-0.7)^5-10(-0.7)^3+9(-0.7) = -3.03807

f(-3)=(-3)^5-10(-3)^3+9(-3) =0

f(3)=(3)^5-10(3)^3+9(3) =0

Therefore the approximate values of the minimum and maximum points of f(x) = x^5- 10x^3+ 9x on [-3,3] are:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.


7 0
3 years ago
Solve for k <br> J = k^2/4 <br> (There can be multiple answers)
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Answer:

The first option is the answer (k = +/- 2 square root of J)

Step-by-step explanation:

Since you need to leave k by itself, You multiply both sides by 4 which will leave you with 4J=k^2. To get rid of the square(^2), you need to square root both sides which will leave k by it self. So now you have 4J inside the square root = k. The last step is to take the square root of 4 (which is + or -2) and put it outside the square root sign, leaving J inside the square root.

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Divide using polynomial long division<br>(x3 + x2 - 9x - 6) ÷ (x2 - 9)​
bixtya [17]

Step-by-step explanation:

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