Question

Please help I’m lost

Answer 1

Answer:

5. 24°

6. 30°

7. 49°

Step-by-step explanation:

5. You are given right triangle with known opposite leg and hypotenuse. By the sine definition,

$\sin \theta=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{11}{27}\\ \\\theta=\sin^{-1}\left(\dfrac{11}{27}\right)\approx 24^{\circ}$

6. You are given right triangle with known opposite leg and hypotenuse. By the sine definition,

$\sin \theta=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{12}{24}=\dfrac{1}{2}\\ \\\theta=\sin^{-1}\left(\dfrac{1}{2}\right)\approx 30^{\circ}$

7. You are given right triangle with known adjacent leg and hypotenuse. By the cosine definition,

$\cos \theta=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{13}{20}\\ \\\theta=\cos^{-1}\left(\dfrac{13}{20}\right)\approx 49^{\circ}$