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GarryVolchara [31]
3 years ago
10

The ratio of females to total students in a mathematics class is 18 to 30. What fraction of the class is male? What percent is m

ale?
Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
6 0

Answer:

2/5 or 40%

Step-by-step explanation:

total students=30

female students=18

That must mean, assuming the rest of the class is binary male=12

12/30=2/5 or 40% if you multiply by 20, then multiply by 100%

(2/5)*20=.40*100%=40%

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3 years ago
If two triangles have three pairs of congruent angles, then the triangles are NOT guaranteed to be congruent. 20 points.
Minchanka [31]

Answer:

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7 0
2 years ago
Helpppppppppp me pleaseeeee
Vlad1618 [11]

Answer:

A = 16   13unit^2 + 9unit^2 = 5 √10 = 15.8 = 16

Step-by-step explanation:

For Pythagoras we square route

= x^2 = 13^13 +  (one of the closer squares for x elimination)

x= 169 + 81        169 + 100       169 + 49   169+64     169 + 121

x = 250    or         269       or     218        or  233     or  290

x= 5√10 or 15.8    or   √269 269   or    √218 2.8     or  √233 or 2.33 ( or  √290 = ( √48+2) or 2.9

6 0
3 years ago
Use the Pythagorean Theorem to find the missing length and then round the
kifflom [539]

Answer:

13.03

Step-by-step explanation:

7 x 7 = 49

11 x 11 = 121

121 + 49 = 170

The square root of 170 is 13.03

Hope this helped!

(And maybe give me brainliest?)

Have a great day!

5 0
3 years ago
Read 2 more answers
Point C divides AB in a particular ratio. Match point C and the ratio into which C divides AB with the endpoints of AB .
Alexandra [31]
In this problem, there is multiple choice for every question. The trick is to exclude the answer that unlikely true.
To solve this easier, you need to find the distance of AB first. After that try to match the answer coordinate with the midpoint of AB. 

1.  Answer: Point C(-3.6, -3.4) divides AB in the ratio 2:3
A (-2,-1) and B(-6, -7)The distance between A and B would be:
x= x2-x1 = -6 - (-2)= -4
y= y2-y1 = -7 - (-1)= -6

Since both x and y coordinate of A and B is minus, let's try answer with x and y minus value.
Point C(-3.6, -3.4) divides AB in the ratio 2:3
x3= x1 + AB ratio* AB distance
x3= -2 + (2/2+3)*(-4)= -3.6

y3= y1 + AB ratio* AB distance
y3= -1 + (2/2+3)*(-6)= -1 - 12/5= -3.4




2.  Point C(0, 1) divides AB in the ratio 4:7
A(4,-3) and B(-7,8)
The distance between A and B would be:
x= x2-x1 = -7 - (4)= -11
y= y2-y1 = 8 - (-3)= 11

Since both x and y distance is 11, let's try answer with total ratio 11

Point C(0, 1) divides AB in the ratio 4:7
x3= x1 + AB ratio* AB distance
x3= 4 + (4/4+7)*(-11)= 4- 4=0

y3= y1 + AB ratio* AB distance
y3= -3 + (4/4+7)*(11)= -3 +4= 1




3. Answer: Point C(8, 9) divides AB in the ratio 5:3
A(3,4) and B(11,12)The distance between A and B would be:
x= x2-x1 = 11 - (3)= 8
y= y2-y1 = 12 - (4)= 8

Since both x and y distance is 8, let's try answer with the total ratio 8. Both of x and y also plus, so focus on coordinate with both x and y plus too.
Point C(3.5, -2.5) divides AB in the ratio 1:7-----> total ratio 8,y minus
Point C(-2, 5) divides AB in the ratio 2:6  -----> total ratio 8, x minus
Point C(8, 9) divides AB in the ratio 5:3   -----> total ratio 8, both x and y plus
x3= x1 + AB ratio* AB distance
x3= 3 + (5/5+3)*(8)= 3+ 5=8

y3= y1 + AB ratio* AB distance
y3= 4 + (5/5+3)*(8)= 4 +5= 9




4. Point C(-2, 5) divides AB in the ratio 2:6  
A(-5,2)and B(7, 14)
The distance between A and B would be:
x= x2-x1 = 7 - (-5)= 12
y= y2-y1 = 14 - (2)= 12

Since both x and y distance is 12, it will be hard to use it since 12 has many factors. Both y coordinate is plus, so focus on coordinate with y more than x and plus.

Point C(4, 1.6) divides AB in the ratio 3:2  ----->  x more than y
Point C(-2, 5) divides AB in the ratio 2:6  -------> y plus, y more than xx3= x1 + AB ratio* AB distance
x3= -5 + (2/2+6)*(12)= -5+ 3=-2

y3= y1 + AB ratio* AB distance
y3= 2 + (2/2+6)*(12)= 2 +3= 5
7 0
3 years ago
Read 2 more answers
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