9514 1404 393
Answer:
slope = 2
Step-by-step explanation:
See the attachment for the markup.
It is usually convenient to choose places where the graph crosses grid intersections. Here, the graph crosses the x- and y-axes at integer values, so those points could be used, for example. We chose points away from the axes so that the rise and run lines could be seen more easily.
The graph has a rise/run of ...
slope = rise/run = 2/1 = 2
The slope of the line is 2.
Answer:
The value of f(z) is not constant in any neighbourhood of D. The proof is as explained in the explaination.
Step-by-step explanation:
Given
For any given function f(z), it is analytic and not constant throughout a domain D
To Prove
The function f(z) is non-constant constant in the neighbourhood lying in D.
Proof
1-Assume that the value of f(z) is analytic and has a constant throughout some neighbourhood in D which is ω₀
2-Now consider another function F₁(z) where
F₁(z)=f(z)-ω₀
3-As f(z) is analytic throughout D and F₁(z) is a difference of an analytic function and a constant so it is also an analytic function.
4-Assume that the value of F₁(z) is 0 throughout the domain D thus F₁(z)≡0 in domain D.
5-Replacing value of F₁(z) in the above gives:
F₁(z)≡0 in domain D
f(z)-ω₀≡0 in domain D
f(z)≡0+ω₀ in domain D
f(z)≡ω₀ in domain D
So this indicates that the value of f(z) for all values in domain D is a constant ω₀.
This contradicts with the initial given statement, where the value of f(z) is not constant thus the assumption is wrong and the value of f(z) is not constant in any neighbourhood of D.
Answer:
idk what this is but plz mark brainliest!
Step-by-step explanation:
I think that its d seems like it might hope this is right
Answer:
Answer is D hope this helps
Step-by-step explanation:
