I hope you are looking for these answer choices as you have not posted the choices. Therefore, I have a similar question with these answer choices.
a). tan² x - 1 = sec²x
b). 4 cosxsinx = 2cos + 1 -2sinx
c). tanx cosx cscx = 1
d). 1- tanx tany = cos(x+y) ÷ cosx cosy
<span>Options B, C, D are correct because, for all them, left-hand side equals to the right-hand side for x = 0.
The option A)
</span>tan² x - 1 = sec²x<span> is not true.
since x = 0
Therefore,
The Right hand side would be:
</span>tan² x - 1 = sec²(0)<span>
= 1
The Left hand side would be:
</span> tan² x - 1 = tan² (0) - 1
= 0 - 1
= -2
Therefore,
Both sides are not equal so it's not a trigonometric identity.
To solve this problem you must apply the proccedure shown below:
1. You have that the formula for calculate the area of a triangle is:
A=bh/2
Where A is the area of the triangle, b is the base of the triangle and h is the height of the triangle.
bh/2=124
bh=124x2
bh=248
2. The problem asks for the new area of the triangle <span>if its base was half as long and its height was three times as long. Then, you have:
Base=b/2
Height=3h
3. Therefore, when you substitute this into the formula for calculate the area of a triangle, you obtain:
A'=bh/2
(A' is the new area)
A'=(b/2)(3)/2
A'=3bh/4
4. When you substitute bh=248 into </span>A'=3bh/4, you obtain:
<span>
A'=186 units</span>²
<span>
The answer is: </span>186 units²
Answer:

Step-by-step explanation:

Step-by-step explanation:
