2. x + y = 82
x - y = 24
---------------add
2x = 106
x = 53
x + y = 82
53 + y = 82
y = 82 - 53
y = 29
solution is : (53,29)
=======================
3. y = 2x
y = 4x + 6
2x = 4x + 6
2x - 4x = 6
-2x = 6
x = -3
y = 2x
y = 2(-3)
y = -6
solution is (-3,-6)
========================
4. 5x + 8y = -29
7x - 2y = -67...multiply by 4
----------------
5x + 8y = -29
28x - 8y = - 268 ..result of multiplying by 4
-----------------add
33x = - 297
x = - 9
5x + 8y = -29
5(-9) + 8y = -29
-45 + 8y = -29
8y = -29 + 45
8y = 16
y = 2
solution is : (-9,2)
=======================
5. y = -4x + 6
y = -5x - 4
-4x + 6 = -5x - 4
-4x + 5x = -4 - 6
x = -10
y = -4x + 6
y = -4(-10) + 6
y = 40 + 6
y = 46
solution is (-10,46)
=========================
6. H(m) = 2m + 12
H(m) = 3m + 10
=========================
7. -8x + 4y > -52
4y > 8x - 52
y > 2x - 13 <==
=========================
8. 3x - y = 28
3x + y = 14
---------------add
6x = 42
x = 7
3x - y = 28
3(7) - y = 28
21 - y = 28
-y = 28 - 21
-y = 7
y = -7
solution is (7,-7)
=====================
10. 5x - 5y > 70
-5y > -5x + 70
y < x - 14 <==
=====================
11. sorry...dont know
=====================
12. y = 4x + 4
y = -3x - 3
4x + 4 = -3x - 3
4x + 3x = -3 - 4
7x = -7
x = -1
y = 4x + 4
y = 4(-1) + 4
y = 0
solution is (-1,0)
=======================
13. -12x - 2y > - 42
-2y > 12x - 42
y < -6x + 21 <==
=======================
14. -5x + 2y = 9
3x + 5y = 7
solution is (-1,2)
========================
15. 3x + 6y = -2
15x + 30y = -10....divide by 5 to reduce = 3x + 6y = -2
is the same line....infinite solutions
========================
1. (the graph).....y < = 3x - 4....3rd one
========================
9. (2nd graph)....y < = -3x + 4....last one
Answer:
K is either 9 or 1
Step-by-step explanation:
Sqrt((0 - 3)² + (k - 5)²) = 5
Square both sides
(0 - 3)² + (k - 5)² = 5²
(0 - 3)² + (k - 5)² = 25
-3² + (k - 5)² = 25
9 + (k-5)(k-5) = 25
9 + k² - 5k - 5k + 25 - 25 = 0
k² - 10k +9 = 0
k² - 9k - k + 9 = 0
k(k - 9) - 1(k - 9) = 0
k - 1 = 0 ; k = 1
k - 9 = 9; k = 1
K = 9 or k = 1
K is either 9 or 1
It would be A, most definitely.
I have no clue. im on that same question
