A Rhombus has four equal straight sides. We can assume that the rhombus in this problem is square-shaped with 90° angles.
m1 = 18x ; 90 = 18x ; 90/18 = x ; 5 = x
m2 = x + y ; 90 = 5 + y ; 90 - 5 = y ; 85 = y
m3 = 30z ; 90 = 30z ; 90/30 = z ; 3 = z
x = 5 ; y = 85 ; z = 3
x + y + z ⇒ 5 + 85 + 3 = 93
Answer:
Step-by-step explanation:
Delia's score X 5 = 65
d X 5 = 65
5d=65
Try using the box method. When I do it, it makes multiplying trinomials and binomials like these easier.
Here is how I would set up the equation:
as you can see in the picture below I multiplied x by 3x^2, -4x, and positive six which gives me a product of 3x^3 (when multiplying always add the exponents) -4x^2 and 6x. Afterwards I did the same thing by multiplying one to the trinomials (3x^2, -4x and 6). Now to simplify the answer you will add by like terms. So -4x^2 plus 3x^2= -x^2
6x+(-4x)= 2x. Since the only two numbers left (6 and 3x^3 aren’t like terms, you leave it like that. Your answer will be 3x^3 + (-x^2)+2x+6.
Answer:
C
Step-by-step explanation:
C 160/2 = 80
240/3 = 80
400 / 5 = 80
480 / 6 = 80
C is linear
Area: 20 x 30 so 600
perimeter: 20 + 20 + 30 + 30 = 100