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Nataliya [291]
2 years ago
9

Riley invested $1000 in saving Spohn, if the bonds earn 6.5% interest and the compounded semi annually how much total Riley earn

in 15 years?
Mathematics
1 answer:
KATRIN_1 [288]2 years ago
6 0

Answer:

$2,610.37

Step-by-step explanation:

The computation of the amount that should be earn in 15 years is shown below:

As we know that

Future value = Present value × (1 + rate of interest)^number of years

= $1,000 × (1 + 6.5% ÷ 2)^15 × 2

= $1,000 × (1 + 3.25%)^30

= $1,000 × 2.610368439

= $2,610.37

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Goshia [24]
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6 0
3 years ago
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Ling worked three more hours on Tuesday than she did on Monday. On Wednesday, she worked one hour more than twice the number of
Nina [5.8K]

Let x be the number of hours ling work on monday.

We know that she worked three more hours on tuesday that in monday, this can be express as :

 x+3

We also know that in wednesday she worked on more hour than twice the number on mondays, this can be expressed as:

2x+1

The total number of hours she worked this three days in two more than five the number of hours she worked on monday, this can be express as :

5x+2\\

Now , once we have all the expressions we add the expressions of the days and equate them to the total

x+(x+3)+(2x+1)=5x+2

Now we solve the equation

x+(x+3)+(2x+1)=5x+2\\x+x+3+2x+1=5x+2\\4x+4=5x+2\\5x-4x=4-2\\x=2

Therefore , she worked 2 hours on monday.

PLEASE MARK ME AS BRAINLIEST

7 0
2 years ago
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I think I know this much so far for A (but I could be wrong):
Eduardwww [97]
Part A. You have the correct first and second derivative.

---------------------------------------------------------------------

Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.

-------------------------------------------------------------

Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out

To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h  ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0. 
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well. 
6 0
3 years ago
Three of the thirty computers are out of service (not working). What percent are working?
AveGali [126]

Answer:

Percentage of computers working equals:

90%

Step-by-step explanation:

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Total computers=30

Percentage of working computers=

                                                       =  

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Hence, Percentage of computers working is:

90%

3 0
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IceJOKER [234]

Answer:

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3 years ago
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