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shutvik [7]
3 years ago
5

How many vertices does this shape have?

Mathematics
1 answer:
BaLLatris [955]3 years ago
6 0
It has six vertices. vertices are the points when the lines come together
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What is the length of the hypotenuse of a right triangle with leg lengths of 8 inches and 15 inches?
stepan [7]
8^2=64 15x15= 225 225+64=289 and the square root of 289 is 17
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How many months have 28 days in it
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Only February unless its on leap year, then February has 29...
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How many books can be stacked on top of one another inside a cupboard 1.21 m high on the inside, knowing that the thickness of e
kvasek [131]

Answer:

10 books approx

Step-by-step explanation:

Step one:

Given data

Hight of cupboard= 1.21m

Thickness of book= 12.5cm

thickness in meters= 12.5/100= 0.125m

Required

The number of books need to fill the Cupboard

Step two:

the number of books can be computed as

= 1.21/0.125

=9.68 book

=10 books approx

4 0
3 years ago
You have been invited to be part of the planning committee for the County Fair. In order to be an effective member you will need
elena55 [62]
Firstly let's find the dimension of this large rectangle:(given)

Area of Rectangle = 660 x 66 =43,560 ft²

And we know that 1 acre = 43,560 ft², then each rectangle has an area of 1 acre & the 20 acres will correspond to 20 x 43560 = 871,200 ft²

We know that the 20 acres form a rectangle. We need to know what is their disposition:

1) We would like to know the layout of the rectangles since we have 4 possibilities FOR THE LAYOUTS

Note that W=66 & L=666 = 43,956 ft²/ unit )

lay out shape could be either:(in ft)
1 W by 20 L  (Final shape Linear 66 x 13320 = 879,120) or
2 W by 10 L  (Final shape Stacked  132 x 6660 = 879,120) or
4 W by   5 L  (Final shape Stacked  264 x 3330 = 879,120) or

2) We would like to know the number of participants so that to allocate equal space as well as the pedestrian lane, if possible, if not we will calculated the reserved space allocated for pedestrian/visitors)

3) Depending on the shape given we will calculate the visitor space & we will deduct it from the total space to distribute the remaining among the exhibitors.

4) (SUGGESTION) Assuming it's linear, we will reserve
20ft x 13320 ft = = 266,400 ft² and the remaining 612,720 ft² for exhibitors
5) Depending on the kind of the exhibition, we will divide the 612,720 ft² accordingly
6) How can we select the space allocated for each exhibitor:
 the 617,720 ft² could be written as a product of prime factors:
612720 = 2⁴ x 3² x 5 x 23 x 37
If you chose each space will be185 ft² , then we can accommodate up to 3,312 exhibitors.
Obviously you can choose any multiple of the prime factors to specify the area allocated & to calculate the number of exhibitors accordingly





3 0
3 years ago
As a decimal 6 27/100​
Brut [27]

Answer:

6.27

Step-by-step explanation:

627100=6+27100

We know that

27100

is the same as

27÷100

Therefore:

627100=6+(27÷100)

8 0
4 years ago
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