3 years ago

What is the length of the hypotenuse of a right triangle with leg lengths of 8 inches and 15 inches?

1 answer:

stepan [7]3 years ago

4 0

8^2=64 15x15= 225 225+64=289 and the square root of 289 is 17

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Lina20 [59]

Answer:

The answer is 3418.1 ft rounded to the nearest tenth.

Step-by-step explanation:

The total volume of the cylinder can be defined by the Area of circular base * Perpendicular height.

The area of the circular base can be calculated as

$\pi \times {r}^{2}$

where r is the radius of the circular base, which is 8 ft.

The area of the circular base is

$\pi \times {8}^{2} = 64\pi$

We also know the height of the cylinder is 17 ft.

Hence, the volume of the cylinder is

$64\pi \times 17 = 1088\pi = 3418.0528...$

This will be rounded up to 3418.1 with the nearest tenth

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3 years ago

ra1l [238]

It is already in identity.
cos (x - y) - cos (x + y) = 2 sin(x) sin (y)

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3 years ago

makvit [3.9K]

250+x might be the right answer because of 250 PLUS the current balance so the current balance would stand for x

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3 years ago

prisoha [69]

130 is the answer. hope this helps

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3 years ago

Bas_tet [7]

Answer:Find the quotient in SIMPLEST form: D) 16

Step-by-step explanation:

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3 years ago