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irina1246 [14]
3 years ago
10

Tim is dividing up a 2 ½ pound bag of nuts into smaller portions.

Mathematics
1 answer:
blondinia [14]3 years ago
3 0

9514 1404 393

Answer:

  a.  10

  b.  5

  c.  3 with 1/4 pound left over

Step-by-step explanation:

You can find the number of 1/4 pound bags by dividing 2 1/2 pounds by 1/4 pound. In decimal, this is obvious:

  2.5/0.25 = 10

Using fractions, it is ...

  (2 1/2)/(1/4) = (5/2)/(1/4) = (10/4)/(1/4) = 10/1 = 10

__

a) Tim can make 10 1/4-pound bags from 2 1/2 pounds.

__

b) It is worthwhile to note that a 1/2-pound bag is equivalent to two 1/4-pound bags. So, the number of 1/2-pound bags will be 10/2 = 5.

Tim can make 5 1/2-pound bags from 2 1/2 pounds.

__

c) It is worthwhile to note that a 3/4-pound bag is equivalent to three 1/4-pound bags. So, the number of 3/4-pound bags will be 10/3 = 3 1/3.

Tim can make 3 3/4-pound bags from 2 1/2 pounds, with 1/4 pound left over.

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Pretty Pavers company is installing a driveway. Below is a diagram of the driveway they are
prohojiy [21]

Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

Therefore, the length of the sides of the square = √3 ft.

Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

Area of the small semicircle = (π·r²)/2 = (π×(5·√3)²)/2 = 117.81 ft.²

Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (\theta - sin\theta) \times r^2

Where:

\theta = 2\times tan^{-1}( \frac{The \, number \, of  \, vertical  \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle}{The \, number \, of  \, horizontal \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle} )

\therefore \theta = 2\times tan^{-1}( \frac{10\cdot \sqrt{3} }{5\cdot \sqrt{3}} ) = 2.214

Hence;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (2.214 - sin2.214) \times (11\cdot\sqrt{3} )^2 = 128.3 \, ft^2

Therefore; t

The area covered by the pavers = 561 - 128.3 + 570.2 - 117.81 = 885.19 ft²

Therefor, the most correct option is (B) 958.2 ft.².

4 0
3 years ago
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Naya [18.7K]

Answer:

-10

Step-by-step explanation:

3/5(b)=-6

Divide -6 by 3/5, you get -30/3.

4 0
3 years ago
There were 13,531 new products introduced last year. If 87% of the products introduced last year failed to reach their business
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Answer:

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