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algol13
2 years ago
9

Review the proof.A 2-column table with 5 rows. Column 1 is labeled step with entries 1, 2, 3, 4, 5. Column 2 is labeled Statemen

t with entries Tangent (StartFraction theta Over 2 EndFraction) = StartRoot StartFraction 1 minus cosine (x) Over 1 cosine (x) EndFraction EndRoot, Tangent (StartFraction theta Over 2 EndFraction) = (StartFraction StartRoot 1 minus cosine (x) EndRoot Over StartRoot 1 cosine (x) EndRoot EndFraction) (StartFraction question mark Over StartRoot 1 cosine (x) EndRoot EndFraction), Tangent (StartFraction theta Over 2 EndFraction) = StartFraction StartRoot 1 minus cosine squared (x) EndRoot Over 1 cosine (x) EndFraction, Tangent (StartFraction theta Over 2 EndFraction) = StartFraction StartRoot sine squared (x) EndRoot Over 1 cosine (x) EndFraction, Tangent (StartFraction theta Over 2 EndFraction) = StartFraction sine (x) Over 1 cosine (x) EndFraction.Which expression will complete step 2 in the proof?
the answer is d im just adding this to brainly for others to find
Mathematics
1 answer:
mariarad [96]2 years ago
5 0
Oh ok it is helpful
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7 0
3 years ago
What is the distance between (4,7) and (2,2)?
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\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ 4}}\quad ,&{{ 7}})\quad 
%  (c,d)
&({{ 2}}\quad ,&{{ 2}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
d=\sqrt{(2-4)^2+(2-7)^2}\implies d=\sqrt{(-2)^2+(-5)^2}
\\\\\\
d=\sqrt{4+25}\implies d=\sqrt{29}
7 0
2 years ago
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