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3 years ago

2. What is an

Mathematics

1 answer:

victus00 [196]3 years ago

6 0

Answer:

the awnser should be. slow and fast

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How do I solve this equation by completing the square. 4X^2 + 12x +5 = 21

Artyom0805 [142]

The Answer is: x1=-4 x2=1.

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3 years ago

What is the value of the expression below when z=4?<br> 10z-3

77julia77 [94]

Answer:

Step-by-step explanation:

10z - 3 = 10(4) - 3

=40-3

=37

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3 years ago

Read 2 more answers

The function h is defined as follows.

JulsSmile [24]

Answer:

The equation you are given is a quadratic. The standard form of a quadratic is y = a(x-h)2 + k where (h,k) is the vertex of the graph, which is a parabola. Vertically moving the graph 4 units upward means that you are moving k +4 units.

y = a(x-h)2 + k standard form

y = 5x2 - 4 original equation

y = 5(x-0)2 - 4 re-written in standard form

h = 0 k = -4

Four (4) units up is k + 4--->-4 + 4 = 0.

Therefore, f(x) = 5x2 + 0--->f(x) = 5x2.

Step-by-step explanation:

hope this helps

plz mark brainliest

3 0

2 years ago

A lift driver charges $5.25 for the first mile of the trip and$1.25 each mile after that. He charges the customer $24 for the ri

WARRIOR [948]

Answer: 15 miles

Step-by-step explanation:

The equation is 5.25+1.25x=24 where x is each additional mile so to solve for x it would be 1.25x=18.75 and divide both sides to solve for x

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3 years ago

Read 2 more answers

Joey and Armando live on the same st as the park. The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando'

AleksandrR [38]

Let's start by assuming Armando's house is between Joey's and the park.

Let $x$ be the distance Joey walked to Armando's house.

<span>The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park.

</span> $\dfrac{9}{10} = x + \dfrac{3}{5}$

$x = \dfrac{9}{10} - \dfrac{3}{5} = \dfrac{9}{10} -\dfrac{6}{10} = \dfrac{3}{10}$

That's probably the answer they're looking for. But what if the park is between Joey and Armando's houses or Joey is between the park and Armando? (The latter isn't really possible with the given distances.)

Let $a, b, c$ be the distances between three collinear points like we have here. Our equation is really a few equations in one, something like

$\pm a \pm b = \pm c$

Let's get rid of the plus/minuses. Squaring,

$a^2 + b^2\pm 2ab = c^2$

$\pm 2ab = c^2-a^2-b^2$

$4a^2b^2 = (c^2-a^2-b^2)^2$

For us, that's a quadratic equation for $c^2$

$4(9/10)^2(3/5)^2= (c^2-(9/10)^2 - (3/5)^2)^2$

I'll skip right to the solutions,

$c^2=\dfrac{9}{100} \textrm{ or } c^2=\dfrac{9}{4}$

$c=\dfrac{3}{10} \textrm{ or } c=\dfrac{3}{2}$

We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.

6 0

4 years ago