36 is the value of 24xyz in those conditions.
Answer:
The percentage of the students scored higher than 89% is 15.87%
Step-by-step explanation:
we are given
The average test scores for a particular test in algebra was 84
so, mean is 84
![\mu=84](https://tex.z-dn.net/?f=%5Cmu%3D84)
a standard deviation of 5
so,
![\sigma=5](https://tex.z-dn.net/?f=%5Csigma%3D5)
we have
x=89
now, we can use z-score formula
![z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
now, we can plug values
![z=\frac{89-84}{5}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B89-84%7D%7B5%7D)
![z=1](https://tex.z-dn.net/?f=z%3D1)
now, we can use calculator
and we get
![p(z>1)=0.1587](https://tex.z-dn.net/?f=p%28z%3E1%29%3D0.1587)
So,
The percentage of the students scored higher than 89% is 15.87%
The answer is A because You have to start at 4 then you <u>add 3 two times</u>