11. You’ve done it correctly
12. Let x^2=y
y^2+13y+40=0
(y+8)(y+5)=0
y=8, 5
Since y=x^2
x^2=8 x^2=5
x=+/-√5 x= +/-2√2
13. x^4-x^2-x^2-8=0
x^4-2x^2-8=0
let x^2=y
Y^2-2y-8=0
(y-4)(y+2)=0
y=4, -2
Since y=x^2
X^2=4 X^2=-2
X= +/- 2 This wouldn’t be a real solution
14. It’s pretty much the same process, just substitute y in for x^2. If you’re confused feel free to ask and I can do it, or you can put it through Photomath
15. You’re on the right track so I’m just going to continue from where you left off
x^2(4x+5)-4(x+5)=0
(x^2-4)(4x+5)=0
x= +/- 2 4x=5
x=5/4 or 1 1/4
Hope this helped :)
Answer:
The producers are simple organisms. The producers are consumed by the consumers in a food chain which may be hetrotrophs like herbivores as well as omnivores. The density or population of the producers is expected to be more so as to feed the large population of the organisms at the higher trophic levels.
Step-by-step explanation:
6/15 + 10/15 = 16/15 = 1 1/15
6/15 - 10/15 = -4/15
16-4 1/8=11 7/8
I hope I've helped!
Answer:
12/(3/4) = 12x4/3 = 16 counters
Step-by-step explanation:
so your answer is 16 counter i redid the math and Nonsibi helped me see where I went wrong sorry
