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tekilochka [14]
4 years ago
13

A teacher bought some bookmarks for her students. if she gave each students 3 bookmarks, she would have 21 bookmarks left. if sh

e gave each students 5 bookmarks, she would be short of 53 bookmarks . How many students does the Teacher have?​
Mathematics
1 answer:
Agata [3.3K]4 years ago
6 0

Answer:

The teacher have 32 students.

Step-by-step explanation:

Firstly, 'if she gave each students 3 bookmarks, she would have 21 bookmarks left.' This means that 3x + 21 = amount of bookmarks available.  Here the x is the number of students.

Then, 'if she gave each students 5 bookmarks, she would be short of 53 bookmarks.' This means that 5x - 53 = amount of bookmarks avalable.

Since both equations all equal to the same quantity, then we know that:

3x + 21 = 5x - 53

Finally, we just need to rearrange the equation to make x the subject.

3x + 21 = 5x - 53

        3x = 5x - 53 - 21

        3x = 5x - 74

 3x - 5x = - 74

      - 2x = - 74

- 2x ÷ -2 = - 74 ÷ -2

           x = 37

Then, just to make sure, we put the number of students into the equations.

    3x + 21 = 5x - 53

3 × 37 + 21= 5 × 37 - 53

     111 + 21 = 185 - 53

           132 = 132  

This means that x does equal to 37.

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Given that,
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<h3>What is congruent geometry?</h3>

In congruent geometry, the shapes that are so identical. can be superimposed on themselves.


Here,
consider ΔABD and ΔCDB
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2. ∠A = ∠C   [each angle of the rectangle is 90°]
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Thus, Both triangles ΔABD ≅ ΔCDB are congruent triangles, hence proved.

Learn more about congruent geometry here. brainly.com/question/12413243

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1 year ago
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AnnyKZ [126]

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Step-by-step explanation:

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3 years ago
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Answer:

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8 0
4 years ago
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timurjin [86]

E=egg farm

x=distantce between  the Berto´s trains and the meeting point.

t=time where the trains meet up

⇒110 miles/h                                          ⇒85miles/h

[---------------------------E----------------------]-------------------------------------X

[............12 miles.......][........34 miles.....][------------ x ----------------------]

distance between Berto´s train and Eduardo´s train=

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S=d/t      ⇒d=S*t

S=seed

d=distance

T=time

Eduardo´s train;

46 miles+x=t*110 miles/h  ⇒x=t*110 miles/h-46 miles  (1)

Berto´s train;

x=t*85 miles/h  (2)

With the equations (1) and (2) we suggest this system equations:

x=t* 110 miles/h-46 miles

x=t*85 miles/h

we solve this system equiations :

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110t miles/h-85t miles/h=46 miles

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