Answer:
63
Step-by-step explanation:
Each term in a geometric sequence progresses by multiplying a constant (let us name it <u>r</u>).
Let us<u> solve for this constant</u> r in order to find the 13th term.
If the seventh term is 7, the tenth term would be 7*r*r*r, or
. We also happen to know that the 10th term is 21. Let us make a <u>new equation</u>:
![7r^{3} =21\\r^{3}=3\\r= \sqrt[3]{3}](https://tex.z-dn.net/?f=7r%5E%7B3%7D%20%3D21%5C%5Cr%5E%7B3%7D%3D3%5C%5Cr%3D%20%5Csqrt%5B3%5D%7B3%7D)
or, approx. 1.442249570307408
Using the same logic, the 13th term would be 7*r*r*r*r*r*r, or
. We may now <u>substitute</u> what we know, r, into this expression to obtain the 13th term:
![7*\sqrt[3]{3}^{6} = \\7*3^{2}=\\7*9=\\63](https://tex.z-dn.net/?f=7%2A%5Csqrt%5B3%5D%7B3%7D%5E%7B6%7D%20%3D%20%5C%5C7%2A3%5E%7B2%7D%3D%5C%5C7%2A9%3D%5C%5C63)
Therefore, the 13th term of this progression is 63.
<em>I hope this helps! Please let me know if you have any further questions :)</em>
Well its pretty hard let me see its 8 by cm and 27 by aera
Answer:
Step-by-step explanation:true by multiplying 6x7=42