Help me please !!! I DONT KNOW WHAT TO PUT PLS HELP ME

Zigmanuir [339]

The answer is 6.35. Because you put in 254 / 40 and it says 6.35.

8 0

3 years ago

Mario is setting up a new tent during a camping trip . The tent came with 7 feet of rope . The instructions are to use 34.5 inch

andrezito [222]

Answer:

The number of $8\frac{1}{4}$ inch sections of a rope Mario can cut from the rope is 6.

Step-by-step explanation:

Given:

Mario is setting up a new tent during a camping trip . The tent came with 7 feet of rope . The instructions are to use 34.5 inches of the rope to a tie the tent stakes in the ground . Mario will use all of the rope as instructed

Now, to write and solve equation to determine the number of 8 1/4 inch sections of a rope Mario can cut from the rope.

Let the number of sections be $x.$

The length of rope Mario can cut from the rope = $8\frac{1}{4} =\frac{33}{4} \ inch.$

Total length of rope = 7 feet.

So, 1 feet = 12 inches.

Thus, the length of rope in inches = 7 × 12 = 84 inches.

The length of rope to tie the tent stakes in the ground = 34.5 inches.

According to question:

Now, to get the number of sections we put an equation:

$x\frac{33}{4} =(84-34.5)$

$x\times \frac{33}{4} =49.5$

$x\times 8.25=49.5$

Dividing both sides by 8.25 we get:

$x=\frac{49.5}{8.25}$

$x=6.$

The number of sections = 6.

Therefore, the number of $8\frac{1}{4}$ inch sections of a rope Mario can cut from the rope is 6.

6 0

4 years ago

I am so confused. Help.

natulia [17]

$\large\sf\underline{ANSWER:}$

√3

x is the length of the third side

x²+1² = 2² { Pythagorean Theorem}

x²+1 = 4 {Simplify}

x²=3 {Subtract 1 from each side}

x=√3 {Take the square root of each side}

The Length of the third side is √3

# $\large\sf\underline{CarryOnLearning}$

4 0

2 years ago

Given h(x)=5x+1, find h(2)

Ket [755]

Answer: h(2) = 11

Step-by-step explanation:

Plug in 2 for x

5(2)+1

10+1

11

6 0

3 years ago

Read 2 more answers

Sets A and B are independent events and are mutually exclusive

Lynna [10]

The solutions are ${P}({A} \text { and }B})=0$ and $P}({A} \text { or } {B})=\frac{7}{12}$

Explanation:

Given that the sets A and B are independent events and are mutually exclusive events.

We need to determine the value of $P(A \text { and } B)$ and $P(A \text { or } B)$

The value of $P(A \text { and } B)$ :

Since, the sets A and B are mutually exclusive events, it is impossible for the two events to occur together.

Hence, we have,

${P}({A} \text { and }B})=0$

Thus, the value of $P(A \text { and } B)$ is 0.

The value of $P(A \text { or } B)$ :

For mutually exclusive events, the value of $P(A \text { or } B)$ is given by the formula,

$P(A \text { or } B)=P(A)+P(B)$

Substituting the values, we get,

$P(A \text { or } B)=\frac{1}{4}+\frac{1}{3}$

$P}({A} \text { or } {B})=\frac{7}{12}$

Hence, the value of $P(A \text { or } B)$ is $\frac{7}{12}$

Thus, the solutions are ${P}({A} \text { and }B})=0$ and $P}({A} \text { or } {B})=\frac{7}{12}$

8 0

4 years ago