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artcher [175]
3 years ago
9

I’ll mark you brainlist I’ll mark you brainlist

Mathematics
2 answers:
Nonamiya [84]3 years ago
7 0
The correct answer would be (2,3) because the line is facing upwards slanted at the right meaning positive. And following the points that are touched on the line would give you (3,2)
In-s [12.5K]3 years ago
4 0

Answer:

2,-4

Step-by-step explanation:

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Charmaine, Hans and Tom have a total of $84 in their wallets. Tom has 3 times what Charmaine has. Hans has $9 more than Charmain
Svet_ta [14]

Tom has $252, Hans has $93 and Charmaine still has $84.

8 0
3 years ago
Anyone know this geometry question?
mr Goodwill [35]
Given:
  ∠JEK + ∠DFH = 90°

Find:
  relationship, if any, of ∠JEK to angles CFL, HFG, LFE

Solution:
  We note that ∠DFG = 90° = ∠DFH + ∠HFG, so ∠JEK ≅∠HFG.
  We also note that ∠HFG and ∠CFL are vertical angles, so ∠JEK ≅∠CFL.
  And ∠LFE and ∠DFH are vertical angles, so ∠JEK + ∠LFE = 90°.

Evaluating the choices, we find
  A) false. The angles are not complementary, they are equal.
  B) false. The angles are not equal, they are complementary.
  C) false. The angles are not supplementary, they are equal.
  D) TRUE. The angles are equal.

The appropriate choice is ...
  D) 
 ∠JEK ≅∠CFL
6 0
3 years ago
Part B
SVEN [57.7K]

Answer:

$500

Step-by-step explanation:

substitute the values for X & S in the equation from part A:

y=20x + 0.15s

x=($20x25) + (0.15x$0)

= $500

3 0
3 years ago
A basketball shot is taken from a horizontal distance of 5m from the hoop. The height of the ball can be modelled by the relatio
olasank [31]
This is the concept of application of quadratic expressions. Given that the height of the ball is modeled by the equation;
h=-7.3t^2+8.25t+2.1+5
The time taken for the ball to hit the ground will be given as falls;
-7.3t^2+8.25t+7.1=0
to solve for t we use the quadratic formula;
t=[-b+/-sqrt(b^2-4ac)]/(2a)
a=-7.3, b=8.25, c=2.1
t=[-8.25+/-sqrt[8.25^2+4*7.3*7.1]/(-2*7.3)
t= -0.572
or
t=1.702
since there is not negative time we take the time taken for the ball to hit the ground will be: t=1.702 sec

7 0
3 years ago
Suppose a and b are the solutions to the quadratic equation 2x^2-3x-6=0. Find the value of (a+2)(b+2).
KonstantinChe [14]

Answer:

(a+2)(b+2) = 4

Step-by-step explanation:

We are given the following quadratic equation:

2x^2-3x-6=0

Let a a and b be the solution of the given quadratic equation.

Solving the equation:

2x^2-3x-6=0\\\text{Using the quadratic formula}\\\\x = \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\text{Comparing the equation to }ax^2 + bx + c = 0\\\text{We have}\\a = 2\\b = -3\\c = -6\\x = \dfrac{3\pm \sqrt{9-4(2)(-6)}}{4} = \dfrac{3\pm \sqrt{57}}{4}\\\\a = \dfrac{3+\sqrt{57}}{4}, b = \dfrac{3-\sqrt{57}}{4}

We have to find the value of (a+2)(b+2).

Putting the values:

(a+2)(b+2)\\\\=\bigg(\dfrac{3+\sqrt{57}}{4}+2\bigg)\bigg(\dfrac{3-\sqrt{57}}{4}+2\bigg)\\\\=\bigg(\dfrac{11+\sqrt{57}}{4}\bigg)\bigg(\dfrac{11-\sqrt{57}}{4}\bigg)\\\\=\dfrac{121-57}{156} = \dfrac{64}{16} = 4

3 0
2 years ago
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