TW x WU = CW x VW
Fill in the known values:
WU = TU - TW = 21.2 - 14.6 = 6.6
14.6 x 6.6 = 6 x VW
Simplify:
96.36 = 6VW
Divide both sides by 6:
VW = 96.36 / 6
VW = 16.06
Round to one decimal place:
VW = 16.1
The answer is D>
Answer:
i am doing this it the letter c d
Step-by-step explanation:
Answer:
Option B is right
Step-by-step explanation:
P(A or B)
In set theory if A and B are two sets we have either A occurs or B occurs or both as
P(A or B) = P(AUB)
This implies that A occurs or B occurs
Probability is calculated as P(A)+P(B)-P(AB)
P(AB) here represents both occurring and this is subtracted as this was added two times
Option A is wrong because this is AB
Option C is wrong because it is not necessary A occurs first
D is wrong because this is A'UB' where A' represents the complement of A
So correct answer out of four options is
B. the probability that in a single trial, event A occurs, event B occurs, or they both occur.
Answer:
35.5 is the average of 34 and 37
Step-by-step explanation:
sqrt (3/10)
sqrt(3)/sqrt(10)
no sqrt in the denominator, so multiply by sqrt(10)/sqrt(1)
sqrt(3) sqrt(10)
-------------------
sqrt(10) sqrt(10)
sqrt(30)/10
Choice D
