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3 years ago

Need help on #25 please!! Show your work

Mathematics

2 answers:

igor_vitrenko [27]3 years ago

7 0

Total of 90 pieces of art. and 10 are sculptures. 10:90 or 1:9

hjlf3 years ago

6 0

10 : 90; 10÷10= 1; 90÷10= 9; 1:9 or 1/9
Hope this helps

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If you are making a scale drawing of a girrafe that is 6m tall, and the height of the girrafe in your drawing is 3cm, what is th

k0ka [10]

Answer:

1cm to 200cm

Step-by-step explanation:

l of giraffe = 6m = 600cm

l of giraffe drawing = 3cm

scale = drawing : real = 3 : 600 = 1 : 200

Therefore the scale is 1cm to 200cm

8 0

2 years ago

Find an equation for the line with the given properties. Perpendicular to the line x - 6y = 8; containing the point (4,4) O 1) y

Pepsi [2]

Answer:

Option 3 - $y=-6x+28$

Step-by-step explanation:

Given : Perpendicular to the line $x - 6y = 8$ ; containing the point (4,4).

To Find : An equation for the line with the given properties ?

Solution :

We know that,

When two lines are perpendicular then slope of one equation is negative reciprocal of another equation.

Slope of the equation $x - 6y = 8$

Converting into slope form $y=mx+c$ ,

Where m is the slope.

$y=\frac{x-8}{6}$

$y=\frac{x}{6}-\frac{8}{6}$

The slope of the equation is $m=\frac{1}{6}$

The slope of the perpendicular equation is $m_1=-\frac{1}{m}$

The required slope is $m_1=-\frac{1}{\frac{1}{6}}$

$m_1=-6$

The required equation is $y=-6x+c$

Substitute point (x,y)=(4,4)

$4=-6(4)+c$

$4=-24+c$

$c=28$

Substitute back in equation,

$y=-6x+28$

Therefore, The required equation for the line is $y=-6x+28$

So, Option 3 is correct.

8 0

2 years ago

What is the sum of forty-six and ninety-four?

lbvjy [14]

Answer:

140

Step-by-step explanation:

46+94 = 140

8 0

2 years ago

Read 2 more answers

An apartment building has a parking lot with 12 parking spaces for tenants. At 6 a.m., all 12 spaces were full. At 8 a.m., the n

nadya68 [22]

Answer:

...80u9

Step-by-step explanation:

6 0

3 years ago

g If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds

dezoksy [38]

Answer:

The number of ways to select 5 diamonds and 3 clubs is 368,082.

Step-by-step explanation:

In a standard deck of 52 cards there are 4 suits each consisting of 13 cards.

Compute the probability of selecting 5 diamonds and 3 clubs as follows:

The number of ways of selecting 0 cards from 13 hearts is:

${13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1$

The number of ways of selecting 3 cards from 13 clubs is:

${13\choose 3}=\frac{13!}{3!\times(13-3)!} =\frac{13!}{13!\times10!}=286$

The number of ways of selecting 5 cards from 13 diamonds is:

${13\choose 5}=\frac{13!}{5!\times(13-5)!} =\frac{13!}{13!\times8!}=1287$

The number of ways of selecting 0 cards from 13 spades is:

${13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1$

Compute the number of ways to select 5 diamonds and 3 clubs as:

${13\choose0}\times{13\choose3}\times{13\choose5}\times{13\choose0} = 1\times286\times1287\times1=368082$

Thus, the number of ways to select 5 diamonds and 3 clubs is 368,082.

6 0

2 years ago