<h2>
Answer:</h2>
<u><em>Thank you for the free points!</em></u>
<u><em>45 + 45 = 90</em></u>
<u><em>45 + 45 + 90 = 180</em></u>
<h2>
Step-by-step explanation:</h2>
<em>Have a good one!</em>
<h2>
☜(ˆ▿ˆc)</h2>
Answer:
Since 60° is one sixth of the entire circle (360°) it means that the length of arc B is 1/6 th of the circumference.
1/6 * (12 * 2π) = 4π
Answer: Option A
The median is the same as the _ Second quartile_.
Step-by-step explanation:
Given a series of data ordered from least to greatest, the median is the value that is in the center.
That is, the median represents the value that divides 50% of the data.
In the same way, the first quartile
is the value that divides 25% of the data and the third quartile
is the value that divides 75% of the data.
The second quartile
is the number that divides 50% of the data.
Then notice that the second quartile is equal to the median
Then te answer is the option A.
The given sequence;–3.2, 4.8, –7.2, 10.8, is a geometric progression common ratio of -1.5.
<h3>What is a geometric series?</h3>
When all the terms of a geometric sequence are added, then that expression is called geometric series.
The given sequence ;
–3.2, 4.8, –7.2, 10.8, …
The common ratio
= -4.8/ 3.2
= - 1.5
The terms having a common ratio of -1.5 best describe the relationship between the successive terms in the sequence of the terms.
Learn more about geometric sequence here:
brainly.com/question/2735005
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Answer:
The best choice would be hiring a random employee from company A
Step-by-step explanation:
<em>Supposing that the performance rating of employees follow approximately a normal distribution on both companies</em>, we are interested in finding what percentage of employees of each company have a performance rating greater than 5.5 (which is the mean of the scale), when we measure them in terms of z-scores.
In order to do that we standardize the scores of both companies with respect to the mean 5.5 of ratings
The z-value corresponding to company A is

where
= mean of company A
= 5.5 (average of rating between 1 and 10)
s = standard deviation of company A

We do the same for company C

This means that 27.49% of employees of company C have a performance rating > 5.5, whereas 71.42% of employees of company B have a performance rating > 5.5.
So, the best choice would be hiring a random employee from company A