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2 years ago

Please help me with my math homework :D (I'll mark brainliest)

Mathematics

2 answers:

EastWind [94]2 years ago

5 0

Answer:

I believe the answer is A

Step-by-step explanation:

pls dont report me if wrong

Zarrin [17]2 years ago

3 0

It’s d, not a! its because since z is greater than x, its d!

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What is the answer to this math equation(x+5)(x²-3x)

Nikolay [14]

Answer:

$x=-5\\x=0\\x=3$

Step-by-step explanation:

I assume your equation to solve is

$(x+5)(x^2-3x)=0$

When we have a product of two factors equal to zero,

$A\cdot B = 0$

The solution is either A = 0 or B = 0.

In this case, this means that we can break the equation into two equations:

$x+5=0\\x^2-3x=0$

Solving the first one, we get:

$x+5=0 \rightarrow x = -5$

For the second one, we rewrite it as:

$x^2-3x=0\\x(x-3)=0$

And we see that this equation has two solutions:

$x=0\\x=3$

Therefore, the three solutions are:

$x=-5\\x=0\\x=3$

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3 years ago

A group of friends count the coins they have in their pockets.

Len [333]

Answer:

The median stays the same, whilst the mean drops.

Step-by-step explanation:

4 0

2 years ago

What is the range of the function y = x 2?

Leno4ka [110]

Answer:

$\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

The graph is also attached below.

Step-by-step explanation:

Given the function

$y=x^2$

We know that the range of a function is the set of values of the dependent variable for which a function is defined.

$\mathrm{For\:a\:parabola}\:ax^2+bx+c\:\mathrm{with\:Vertex}\:\left(x_v,\:y_v\right)$

$\mathrm{If}\:a$

$\mathrm{If}\:a>0\:\mathrm{the\:range\:is}\:f\left(x\right)\ge \:y_v$

$a=1,\:\mathrm{Vertex}\:\left(x_v,\:y_v\right)=\left(0,\:0\right)$

$f\left(x\right)\ge \:0$

Thus,

$\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

The graph is also attached below.