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ValentinkaMS [17]
3 years ago
10

Explain how to work out these type of questions please!

Mathematics
2 answers:
e-lub [12.9K]3 years ago
8 0
In these types of problems, you have to get x alone, so you have to get rid of the x’s denominator that is 5. To do this, you will multiply both sides by 5. The 5 in the x/5 with cancel and leave only an x.

The next answer would be x=9 times 5 because of this. Then you will just do 9 times 5, which is 45. So the final answer is x=45.
bixtya [17]3 years ago
7 0

x = 9 \times 5 \\ x = 45
Hope this helps. - M
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3x - y = 0<br> 2x - y = 1
9966 [12]
Answer: See below

Explanation:
Solve this system of equation using elimination method:

3x - y = 0
2x - y = 1
________
3x - y = 0
-1(2x - y = 1)
_________
3x - y = 0
-2x + y = -1
_________
X = -1

We know that x = -1 now let’s plug it in the one of the equation to find y:

2x - y = 1
2(-1) - y = 1
-2 - y = 1
-y = 3
y = -3

8 0
2 years ago
Find the missing side lengths.Leave your answers in simplest radical form.
lina2011 [118]

Answer:

6) 9 7) 8 8) 7 9) 9

Step-by-step explanation:

5 0
3 years ago
If a 10 symbol sequence is sent through the channel,what is the probability that up to 3 symbols are in error out of the 10trans
lina2011 [118]

Answer: 0.171887

Step-by-step explanation:

Given that S0 and S1 are binary symbol of equal probabilty;

P(S0) = P(S1) = 0.5

This probability is a Binomial random variable of sequence Sn, where Sn counting the number of success in a repeated trials.

P(Sn =X) = nCx p^x (1-p)^(n-1)

Pr(at most 3) = P(0<= x <=3) = P(X=0) + 0) + P(X=1) + P(X=2) + P(X=3)

Since there are only 2 values that occur in sequence 0 and 1 ( or S0 and S1).Let the distribution be given by the sequence (0111111111),(1011111111),(11011111111),...(1111111110) for Sn= 1 is the sequence for 1 error.

10C0, 10C1, 10C2, and 10C3 is the number of sequences in value for X= 0, 1, 2, 3 having value 0 and others are 1. Let the success be p(S0)=0.5 and p(S1)= 0.5

P(0<= X <=3) = 10C0 × (0.5)^0 × (0.5)^10 + 10C1× (0.5)¹ × (0.5)^9 + 10C2 × (0.5)² × (0.5)^8 + 10C3(0.5)³(0.5)^7

= 1 × (0.5)^10 + 10 × (0.5)^10 + 45 × (0.5)^10 + 120 × (0.5)^10

=0.000977 + 0.00977 + 0.04395 + 0.11719

= 0.171887

3 0
3 years ago
What will an investment of 6000 Euro at 7% p.a compound interest amount to after 5 years if the interest is compounded:
Over [174]
S = P[1 + (r / m)]^(m * t) 

S = ? 

P = 6000 euro 

r = 0.07 

m = 12 

t = 5 

S = 6000[1 + (0.07 / 12)]^(12 * 5) 

S = 6000(1.00583)^(60) 

S = 6000(1.4176...) 

<span>S = 8505.75 euro

---------------------------

You can now do the rest which is anually and quarterly.</span>
5 0
3 years ago
Anfernee bought 4 umbrella and 5 hats and spent between $80.00 and 100.00. Each umbrella cost the same amount. Each hat cost the
barxatty [35]

Answer:

$15, $20

Step-by-step explanation:

Let u represent the unit price of umbrellas and h the unit price of hats.

Case 1:  A. spent $80.

Then $80 = 4u + 5($4), or $80 = $20 + 4u, or $60 = 4u, or

u = $15/umbrella.

Case 2:  A spent $100.

Then $100 = 4u + 5($4), or $100 = $20 + 4u, or $80 = 4u, or

u = $20/umbrella.

The least A. could have spent on a single umbrella was $15, and the most was $20.

6 0
3 years ago
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