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3 years ago

Graph the image of rectangle CDEF after a reflection over the line y=x

Mathematics

1 answer:

yulyashka [42]3 years ago

6 0

To find a he correct points, I counted the units each point was from the line of reflection. The. I took that same number of points and did it to find the new point. D’ is at (5,2) E’ is at (10,2) F’ is at (10,-5) And C’ is at (5,-5)

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NEED HELP ASAP

san4es73 [151]

Answer:

t = 25.05761543°

Step-by-step explanation:

sin (x) = 36/85 = 0.423529412

sin (x) = 0.423529412

x = sin^-1(0.423529412)

x = 25.05761543°

4 0

3 years ago

PLEASE HELP ILL MARK BRAINLIEST !!!

Alexus [3.1K]

Answer:

a) the common difference is 20

b) $x_8=115 , x_{12}=195$

c) the common difference is -13

d) $a_{12}=52, a_{15}=13$

Step-by-step explanation:

a) what is the common difference of the sequence xn

Looking at the table, we get x_3=16, x_4=36 and x_5= 56

Deterring the common difference by subtracting x_4 from x_3 we get

36-16 =20

So, the common difference is 20

b) what is x_8? what is x_12

The formula used is: $x_n=x_1+(n-1)d$

We know common difference d= 20, we need to find $x_1$

Using $x_3=16$ we can find $x_1$

$x_n=x_1+(n-1)d\\x_3=x_1+(3-1)d\\15=x_1+2(20)\\15=x_1+40\\x_1=15-40\\x_1=-25$

So, We have $x_1 = -25$

Now finding $x_8$

$x_n=x_1+(n-1)d\\x_8=x_1+(8-1)d\\x_8=-25+7(20)\\x_8=-25+140\\x_8=115$

So, $\mathbf{x_8=115}$

Now finding $x_{12}$

$x_n=x_1+(n-1)d\\x_{12}=x_1+(12-1)d\\x_{12}=-25+11(20)\\x_{12}=-25+220\\x_{12}=195$

So, $\mathbf{x_{12}=195}$

c) what is the common difference of the sequence $a_m$

Looking at the table, we get a_7=104, a_8=91 and a_9= 78

Deterring the common difference by subtracting a_7 from a_8 we get

91-104 =-13

So, the common difference is -13

d) what is a_12? what is a_15?

The formula used is: $a_n=a_1+(n-1)d$

We know common difference d= -13, we need to find $a_1$

Using $a_7=104$ we can find $x_1$

$a_n=a_1+(n-1)d\\a_7=a_1+(7-1)d\\104=a_1+7(-13)\\104=a_1-91\\a_1=104+91\\a_1=195$

So, We have $a_1 = 195$

Now finding $a_{12}$ , put n=12

$a_n=a_1+(n-1)d\\a_{12}=a_1+(12-1)d\\a_{12}=195+11(-13)\\a_{12}=195-143\\a_{12}=52$

So, $\mathbf{a_{12}=52}$

Now finding $a_{15}$ , put n=15

$a_n=a_1+(n-1)d\\a_{15}=a_1+(15-1)d\\a_{15}=195+14(-13)\\a_{15}=195-182\\a_{15}=13$

So, $\mathbf{a_{15}=13}$

5 0

3 years ago

a car travels along a straight road to the east for 150 meters in 4 seconds and west for 50 meters in one second

makvit [3.9K]

a car travels along a straight road to the east for 150 meters in 4 seconds and west for 50 meters in one second

4 0

3 years ago

Point p’ (1,5) is the image of p (-3,1) under a translation<br><br> khan academy

GarryVolchara [31]

Answer:

Step-by-step explanation:

We need to find the translation for which, (-3, 1) becomes (1, 5).

-3 will become 1, if it is divided by -3.

Hence, the translation for x axis is X = $\frac{-x}{3}$ .

1 will become 5, when it is multiplied by 5.

Hence, The translation for y axis is Y = 5y.

6 0

3 years ago

Read 2 more answers

How many terms are in the arithmetic sequence 9, 2, −5, . . . , −187?

Fantom [35]

9, 2, -5... so is going down by 7 each time, meaning the "common difference" is -7.

$\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=9\\
d=-7\\
a_n=-187
\end{cases}
\\\\\\
-187=9+(n-1)(-7)\implies -187=9-7n+7
\\\\\\
7n=9+7+187\implies 7n=203\implies n=\cfrac{203}{7}\implies \boxed{n=29}$

4 0

3 years ago