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rosijanka [135]
2 years ago
15

Factor this trinomial 4x^2-6x-10 If you can please try to show me how to do it.

Mathematics
1 answer:
lilavasa [31]2 years ago
8 0

Answer:

=2(2x-5)(x+1)

Step-by-step explanation:

So we have the trinomial:

4x^2-6x-10

First, factor out a 2:

=2(2x^2-3x-5)

Now, factor within the parentheses.

To do so, we want to find two numbers. When multiplied, these two numbers must equal (a)(c) and when added, they must equal b

(a)(c) is 2(-5) or -10 and b is -3. So, we want two numbers that when multiplied together gives -10 and when added gives -3.

-5 and 2 works. Therefore:

=2(2x^2-3x-5)

Replace -3x with 2x and -5x:

=2(2x^2+2x-5x-5)

Factor out a 2x for the first two terms. And factor out a negative 5 for the remaining two:

=2(2x(x+1)-5(x+1))

Grouping:

=2(2x-5)(x+1)

And we're done!

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$20,000
In word form. he has twenty three thousand five hundred and fifty six, so we look to the digit next to the thousands, 3, and since its below 5, we keep 2 the same.
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3 years ago
Solve for x in the equation (x-3)³​
Alona [7]

Answer:

x4−9x3+27x2−27x : ) Your welcome

7 0
3 years ago
Write the standard equation for the hyperbola with the following conditions: vertices: (-2, -3) and (6, -3) foci: (-4, -3) and (
STALIN [3.7K]
Hello,

Vertices are on a line parallele at ox (y=-3)

The hyperbola is horizontal.

Equation is (x-h)²/a²- (y-k)²/b²=1

Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and  2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)

Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6

c²=a²+b²==>b²=36-4²=20

Equation is:
\boxed{ \dfrac{(x-2)^2}{16} - \dfrac{(y+3)^2}{20} =1}





8 0
2 years ago
Find the sum of the first 42 terms of the following series, to the nearest
balandron [24]

Answer:

Step-by-step explanation:

Find the sum of the first 42 terms of the following series, to the nearest integer.

2,7,12

Solution

The sum is given by  

SUM_n=n/2*(a_1+a_n)

a_n=a_1+(n-1)d

a_1=2,   n=42,     d=5

The 42nd term is therefore given by  

a_42=2+(42-1)5=207

SUM_42=42/2*(2+207)=21*209=4389

The sum of the first 42 terms of the series, therefore, is 4389

5 0
2 years ago
The problem is in the picture.
Semmy [17]

Answer:

  • an = 5 + 10(n -1)
  • a7 = 65

Step-by-step explanation:

The explicit formula for the n-th term of an arithmetic sequence is ...

  an = a1 + d(n -1)

where a1 is the first term and d is the common difference.

The sequence of seat counts has a1=5 and d=10, so the explicit formula is ...

  an = 5 +10(n -1)

___

The 7th term is ...

  a7 = 5 +10(7 -1) = 65

5 0
3 years ago
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