Question 7 of 10

During their last game, the Miami Dolphins scored ͸ times for a total score of ͵Ͳ points. They scored ͹ points for each touchdow

Karolina [17]

Answer:

The Miami Dolphins had 3 touchdowns and 3 field goals.

Step-by-step explanation:

It is given that During their last game, the Miami Dolphins scored 6 times, for a total score of 30 points. They scored 7 points for each touchdown and 3 points for each field goal.

We need to write and solve the system of equations to find the total touchdowns and field goals scored.

Let x represents the number of touchdowns.

Let y be the number of field goals.

It is given that the Miami Dolphins scored 6 times

$x+y=6$

$x=6-y$ ....(1)

They scored 7 points for each touchdown and 3 points for each field goal.

The total score is 30 points:

$7x+3y=30$ ...(2)

Put the value of x from equation (1) into equation (2).

$7( 6-y)+3y=30$

$42-7y+3y=30$

$-4y=30-42$

$-4y=-12$

$y=3$

Put y = 3 in equation 1.

$x=6-3$

$x=3$

Hence, the Miami Dolphins had 3 touchdowns and 3 field goals.

4 0

2 years ago

How to differentiate ?

Bas_tet [7]

Use the power, product, and chain rules:

$y = x^2 (3x-1)^3$

• product rule

$\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{\mathrm d(x^2)}{\mathrm dx}\times(3x-1)^3 + x^2\times\dfrac{\mathrm d(3x-1)^3}{\mathrm dx}$

• power rule for the first term, and power/chain rules for the second term:

$\dfrac{\mathrm dy}{\mathrm dx} = 2x\times(3x-1)^3 + x^2\times3(x-1)^2\times\dfrac{\mathrm d(3x-1)}{\mathrm dx}$

• power rule

$\dfrac{\mathrm dy}{\mathrm dx} = 2x\times(3x-1)^3 + x^2\times3(3x-1)^2\times3$

Now simplify.

$\dfrac{\mathrm dy}{\mathrm dx} = 2x(3x-1)^3 + 9x^2(3x-1)^2 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = x(3x-1)^2 \times (2(3x-1) + 9x) \\\\ \boxed{\dfrac{\mathrm dy}{\mathrm dx} = x(3x-1)^2(15x-2)}$

You could also use logarithmic differentiation, which involves taking logarithms of both sides and differentiating with the chain rule.

On the right side, the logarithm of a product can be expanded as a sum of logarithms. Then use other properties of logarithms to simplify

$\ln(y) = \ln\left(x^2(3x-1)^3\right) \\\\ \ln(y) = \ln\left(x^2\right) + \ln\left((3x-1)^3\right) \\\\ \ln(y) = 2\ln(x) + 3\ln(3x-1)$

Differentiate both sides and you end up with the same derivative:

$\dfrac1y\dfrac{\mathrm dy}{\mathrm dx} = \dfrac2x + \dfrac9{3x-1} \\\\ \dfrac1y\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{15x-2}{x(3x-1)} \\\\ \dfrac{\mathrm dy}{\mathrm dx} = \dfrac{15x-2}{x(3x-1)} \times x^2(3x-1)^3 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = x(15x-2)(3x-1)^2$

7 0

2 years ago

You are given two offers for a monthly wage. Option A is to be paid one cent on the first day of the month, with your wages doub

ira [324]

Answer:

Step-by-step explanation:

Option B

Because if you start with one dollar and by day 3 you get 301 dollars and option A only gives you 8 cents on day 3 you get more money by the end of the month if you choose option B.

5 0

2 years ago

Write the sentence as an inequality

oee [108]

Answer:

X2+4<10

Step-by-step explanation:

7 0

2 years ago

Why is gravity different on other planets?

Sliva [168]

Answer:

2--2-2-2-2-2-2-2-2--2-2-2-2--2

Step-by-step explanation:

7 0

2 years ago

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