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3 years ago

Can somebody please help??

Mathematics

1 answer:

Ksenya-84 [330]3 years ago

6 0

Answer:

-31104

Step-by-step explanation:

They are each Multiplying by 6 so 5184 which also multiply and add the negative sign so you get -31104

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PLEASE HELP x = ___ units

Shkiper50 [21]

Answer:

x = 16 units

Step-by-step explanation:

∆ABC is a 45-45-90 triangle, and ∆BCD is a 30-60-90 triangle.

If side opposite of 90° [∆] = x, side opposite of 45° [∆] = x / √2 = x √ 2 / 2.

Given side AC is opposite of 90° [∆ABC] = 32 √ 2, side opposite of 45° [∆ABC] = 32 √ 2 / √ 2 = 32 which is AB or BC.

Since side BC is part of BCD.

Side opposite of 90° [∆BCD] = BC = 32.

Since x is opposite of 30° [∆BCD].

x = Side opposite of 90° [∆BCD] / 2 = 32 / 2 = 16.

8 0

3 years ago

Wade needs to solve the problem 1 5/8 x - 2 1/2 = -11 4/5. He is not sure what to do first, so he rounds the numbers to take a l

skad [1K]

I hope this helps you

8 0

3 years ago

ozzi

The answer is A. 6 and 10

3 0

3 years ago

Find and simplify each of the following for

WINSTONCH [101]

Answer:

(A) f(x + h) = 4x² + 8xh + 4h² - 6x - 6h + 6

(B) f(x + h) - f(x) = 8xh + 4h² - 6h

Step-by-step explanation:

* Lets explain how to solve the problem

- The function f(x) = 4x² - 6x + 6

- To find f(x + h) substitute x in the function by (x + h)

∵ f(x) = 4x² - 6x + 6

∴ f(x + h) = 4(x + h)² - 6(x + h) + 6

- Lets simplify 4(x + h)²

∵ (x + h)² = (x)(x) + 2(x)(h) + (h)(h) = x² + 2xh + h²

∴ 4(x + h)² = 4(x² + 2xh + h²) = 4x² + 8xh + 4h²

- Lets simplify 6(x + h)

∵ 6(x + h) = 6(x) + 6(h)

∴ 6(x + h) = 6x + 6h

∴ f(x + h) = 4x² + 8xh + 4h² - (6x + 6h) + 6

- Remember (-)(+) = (-)

∴ f(x + h) = 4x² + 8xh + 4h² - 6x - 6h + 6

* (A) f(x + h) = 4x² + 8xh + 4h² - 6x - 6h + 6

- Lets find f(x + h) - f(x)

∵ f(x + h) = 4x² + 8xh + 4h² - 6x - 6h + 6

∵ f(x) = 4x² - 6x + 6

∴ f(x + h) - f(x) = 4x² + 8xh + 4h² - 6x - 6h + 6 - (4x² - 6x + 6)

- Remember (-)(-) = (+)

∴ f(x + h) - f(x) = 4x² + 8xh + 4h² - 6x - 6h + 6 - 4x² + 6x - 6

- Simplify by adding the like terms

∴ f(x + h) - f(x) = (4x² - 4x²) + 8xh + 4h² + (- 6x + 6x) - 6h + (6 - 6)

∴ f(x + h) - f(x) = 8xh + 4h² - 6h

* (B) f(x + h) - f(x) = 8xh + 4h² - 6h

- Lets find $\frac{f(x+h)-f(x)}{h}$

∵ f(x + h) - f(x) = 8xh + 4h² - 6h

∴ $\frac{f(x+h)-f(x)}{h}=\frac{8xh + 4h^{2}-6h}{h}$

- Simplify by separate the three terms

∴ $\frac{f(x+h)-f(x)}{h}=\frac{8xh}{h}+\frac{4h^{2} }{h}-\frac{6h}{h}$

∴ $\frac{f(x+h)-f(x)}{h}=8x+4h-6$

* (C) $\frac{f(x+h)-f(x)}{h}=8x+4h-6$

4 0

3 years ago

What is the missing justification in the proof?

nataly862011 [7]

The missing justification in the proof is
B) Substitution property of equality

The expression for sin² x and cos² x is substituted to the other side of the equation. Since sin x = a/c, then sin² x = a²/c². Similarly, since cos x = b/c, then cos² x = b²/c². Adding to two results to the third statement.

7 0

3 years ago

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