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Lorico [155]
2 years ago
15

1. What is the equation of the vertical line that passes through the point (3, 4)?

Mathematics
1 answer:
Natasha_Volkova [10]2 years ago
5 0

Answer:

1. the Equation of vertical line=> x=3

2. the Equation of horizontal line

=> y = 4

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PLEASE HURRY!!!!!!!
nika2105 [10]

Answer:

The mid-point of the given line segment is:(5.5,-6.5)

Step-by-step explanation:

let us consider two points A and B with coordinates (a,b) and (c,d) respectively.

let C be the mid point of A and B then then the coordinates of C is given by (\frac{a+c}{2},\frac{b+d}{2}).

in the given question (a,b)=(9,-8) and (c,d)=(2,-5) so the mid point of these two points are (\frac{9+2}{2},\frac{-8-5}{2})=(5.5,-6.5)

Hence, the coordinates of the midpoint of the line segment with endpoints B(9,-8) and C(2,-5) is (5.5,-6.5).

8 0
3 years ago
Read 2 more answers
HELP
cupoosta [38]

Answer:

y=-2x+7

Step-by-step explanation:

slope intercept form is equal to y=mx+c

where y is the y value

x is the x value

m is the gradient

and c is the y intercept

so the equation for this set of values is equal to

y=-2x+7

7 0
3 years ago
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A line passing (a,3) and (5,5) is perpendicular to a line passing through (0,0) and (1,a) Find the value of a.
vodka [1.7K]

Answer:

a = -5

Step-by-step explanation:

(5 - 3)/(5 - a)

2/(5 - a)

perpendicular of 2/(5 - a) = -(5 - a)/2

(a - 0)/(1 - 0) = -(5 - a)/2

a/1 = -(5 - a)/2

2a = -5 + a

a = -5

6 0
3 years ago
Slope of a parallel line with the points (7,-5) and (-5,7)
VLD [36.1K]

Answer: Negative 1  The slope of parallel lines is the same.

The attachment shows two such lines, given coordinates labeled.

Step-by-step explanation:

Find the slope of the line passing through the given points.

 rise/run  

Rise is the difference in y-values  7-(-5)  = 12

Run is the difference between x-values  -5 - 7  = - 12

The Slope is 12/-12   simplify:

slope = -1

5 0
3 years ago
COMPLETING THE SQUARE<br> X^2– 2x +
Studentka2010 [4]

Answer:

x^2 -2x + 1

Step-by-step explanation:

Think of a quadratic equation as

ax^2 + bx + c

x^2 -2x +

Comparing the two equations

a = 1 ,  b = -2,  c = ?

c becomes the missing part

Divide b by 2

-2/2 = -1

square the result

-1^2

= 1  this is what to add to get a perfect square

x^2 -2x + 1

(x - 1)^2

6 0
3 years ago
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