Answer:
<em>x + x + 1 + x + 2 + x + 3 + x + 4 + x + 5 + x + 6 = 7(x + 1)</em>
Step-by-step explanation:
<u>Equations</u>
The situation can be written as an algebraic equation by setting the variables as follows:
x = first integer
x + 1 = second integer
x + 2 = third integer
x + 3 = fourth integer
x + 4 = fifth integer
x + 5 = sixth (and last) integer
The sum of all six numbers must be equal to 7 times the second number, thus:
x + x + 1 + x + 2 + x + 3 + x + 4 + x + 5 + x + 6 = 7(x + 1)
Answer:
D
Step-by-step explanation:
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-12. Subtract 8 from both sides.
