Answer:
Masses of bromobenzene molecular ions will occur at 156 and 158 m/z.
Explanation:
The molecular ion peak is the signal in the mass spectrum of a compound that represents the molecular ion (denoted as M). Compounds that are composed of atoms having abundant isotope also shows M +1 and M+2 peaks (depending on the isotope).
In the given bromobenzene compound, an atom of bromine is present. The two isotopes with considerable relative abundance of Br are 79Br and 81Br with a difference of two units in their mass. This means that two molecular ion peaks with a difference of two units will appear in the mass spectrum. The mass of the whole compound is 156 amu. Hence, the molecular ion peaks will appear at 156 m/z and 158 m/z due to the two isotopes of bromine.
If a ball is running down a ramp, why is it that when you change the height of the ramp, the ... of the ramp, then you will increase the acceleration of a ball which rolls down the ramp.
Answer:
Work done on the system is zero , hence no work is done since the process is <u>isochoric.</u> There is no work done if the volume remains unchanged. (Though the temperature rises, work is only accomplished when the volume of the gas changes.)
Explanation:
ISOCHORIC PROCESS - An isochoric process, also known as a constant-volume process, isovolumetric process, or isometric process, is a thermodynamic process in which the volume of the closed system undergoing the process remains constant through the process. The heating or cooling of the contents of a sealed, inelastic container is an example of an isochoric process. The thermodynamic process is the addition or removal of heat, the closed system is established by the isolation of the contents of the container, and the constant-volume condition is imposed by the container's inability to deform. It should be a quasi-static isochoric process in this case.
<u>Hence , the work done in the system is zero.</u>
The element would be Neon. They are found in signs
The concentration of the basic solution is determined by:
N = (number of moles / volume of solution)
number of moles = 1.09 x 10^-2 mol
volume of solution = 1 liter
N of basic solution = 1.09 x 10^-2 mol / 1 liter
N = 1.09 x 10^-2 mol/L
The initial concentration of Zn (OH)2 is 0; the basic solution is 1.09x10^-2 M, then the concentration of OH in the final solution is 1.09x10^-2 M
