Well I’m. Or to sure but it can’t be B because when you throw the ball the the kinetic energy is still increasing
Molar C6H12O6 = 180.15 g/mol
180.15 g -------------- 6.02x10²³ molecules
?? g ------------------- 3.5x10²² molecules
( 3.5x10²²) x 180.15 / 6.02x10²³ =
=> 10.47 g
Ooo im taking chem this semester and just around this subject,
water is neutral and <span>H2CO3cant act as b-l base soo </span>the answer is HCIO4(aq)
Answer : The rate of effusion of sulfur dioxide gas is 52 mL/s.
Solution :
According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.
or,
..........(1)
where,
= rate of effusion of nitrogen gas = 
= rate of effusion of sulfur dioxide gas = ?
= molar mass of nitrogen gas = 28 g/mole
= molar mass of sulfur dioxide gas = 64 g/mole
Now put all the given values in the above formula 1, we get:
Therefore, the rate of effusion of sulfur dioxide gas is 52 mL/s.
The bond angle in H2Se would be predicted should be less than 109.5 degrees. Particle shapes can be anticipated in light of Lewis dab structure utilizing the VSEPR hypothesis. VSEPR remains for Valence Shell Electron Pair Repulsion. It expresses that electron matches in the valence shell of a particle repulse each other; their sub-atomic geometry is the consequence of this shock.
