According to vsepr theory, the bond angle in h2se would be predicted to be:

2 answers:

4 0

The bond angle in H2Se would be predicted should be less than 109.5 degrees. Particle shapes can be anticipated in light of Lewis dab structure utilizing the VSEPR hypothesis. VSEPR remains for Valence Shell Electron Pair Repulsion. It expresses that electron matches in the valence shell of a particle repulse each other; their sub-atomic geometry is the consequence of this shock.

wlad13 [49]3 years ago

3 0

Answer:

109.5°

Explanation:

According to vsepr theory, the bond angle is affected by many factors. Some of these factors are the presence of the lone pairs of electrons. Some, are simply the size of the electron cloud of the atom. The molecule H₂Se is synonymous with the water molecule,H₂O. Water has two LONE PAIRS of electrons on the oxygen atom. This increases the repulsion of the electron clouds giving the molecule a V-shape of 109.5°. Thus, H₂Se has and angle of 109.5° as water molecule

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A. Describe the molecule chlorine dioxide, CIO in terms of three possible resonance structures.

cupoosta [38]

Answer:

See explanation

Explanation:

The compound ClO2 has 19 valence electrons. ClO2 is a bent molecule with tetrahedral electron pair geometry but has two lone pairs of electrons. This is indicated by the presence of four electron pairs on the outermost shell of the central atom.

The molecule has an odd number of valence electrons, hence, it is generally regarded as a paramagnetic radical. None of the proposed Lewis structures for the molecule is satisfactory because none of them obeys the octet rule.

From the images attached, one can easily see that the electron dots around the oxygen and chlorine atoms does not satisfy the octet rule in all the resonance structures shown.