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3 years ago

Pls solve both i’m begging ‍♀️‍♀️

Mathematics

2 answers:

AVprozaik [17]3 years ago

5 0

Answer:

$17 and $3

Step-by-step explanation:

He had $ 5 right, he spent 12 so just add 12. Work backwards. Bella spent 12 dollars on 3 packs because 3 packs * $4 = 12. Hope this makes sense. You just want to use the inverse operation.

1. x - 12 = 5. x = 17

2. 4x = 12. x = 3

riadik2000 [5.3K]3 years ago

3 0

1.) 17 dollars 2.) 3 packs

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Give an example of a repeating decimal where two digits repeat explain why is a rational number

adelina 88 [10]

Answer:

An example of a repeating decimal where two digits repeat is 0.171717..., it is a rational number because you know what comes next

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4 years ago

In 2009, the national debt of a government was about $10.5 trillion. Using 308.0 million as the population for that year, abo

Katarina [22]

Answer:

34091 dollars per person

Step-by-step explanation:

In order to answer the question, you have to divide the amount of debt by the amount of population to obtain the amount of dollars per person.

The debt was $10.5 trillion. A trillion is a thousand billion (1000 multiplied by a billion which is $10^{9}$ in scientific notation)

1000= $10^{3}$

One trillion is $(10^{3})(10^{9})=10^{12}$

The debt is: $ 10.5 x $10^{12}$

The population is scientific notation is: 308.0 x $10^{6}$

Dividing the amount of debt by the amount of population:

$\frac{(10.5)(10^{12})}{(308.0)(10^{6})}=\frac{(10.5)(10^{12-6})}{308.0}=\frac{(10.5)(10^{6})}{308.0}$

Simplifying and expressing it in standard notation:

34090.9 dollars per person

Rounding to the nearest dollar:

34091 dollars per person.

4 0

3 years ago

How do you solve these problems?

Fed [463]

Answer:

Step-by-step explanation:

Hello,

a. The area of region P is the area of the rectangle 1 * e minus the

$\displaystyle \int\limits^0_1 {e^x} \, dx=[e^x]^{1}_{0}=e-1$

So this is e - (e-1) = e - e + 1 = 1

b. The area of region P is the area of the rectangle 1 * e minus P and minus the

$\displaystyle \int\limits^0_1 {e^{-x}} \, dx=[-e^{-x}]^{1}_{0}=-e^{-1}+1$

So this is

$e - 1 - (-e^{-1}+1) = e-1+e^{-1}-1=e+e^{-1}-2$

This is around 1.08616127...

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

8 0

3 years ago

Set up an integral for the volume of the solid obtained by rotating the region bounded by the given curves about the specified l

Sloan [31]

Answer:

The integral of the volume is:

$V = 32\pi\int\limits^1_0 {\sqrt{(1 - y^2)} \, dy$

The result is: $V = 78.97731$

Step-by-step explanation:

Given

Curve: $x^2 + 4y^2 = 4$

About line $x = 2$ --- Missing information

Required

Set up an integral for the volume

$x^2 + 4y^2 = 4$

Make x^2 the subject

$x^2 = 4 - 4y^2$

Square both sides

$x = \sqrt{(4 - 4y^2)$

Factor out 4

$x = \sqrt{4(1 - y^2)$

Split

$x = \sqrt{4} * \sqrt{(1 - y^2)$

$x = \±2 * \sqrt{(1 - y^2)$

$x = \±2 \sqrt{(1 - y^2)$

Split

$x_1 = -2 \sqrt{(1 - y^2)}\ and\ x_2 = 2 \sqrt{(1 - y^2)}$

Rotate about x = 2 implies that:

$r = 2 - x$

So:

$r_1 = 2 - (-2 \sqrt{(1 - y^2)})$

$r_1 = 2 +2 \sqrt{(1 - y^2)}$

$r_2 = 2 - 2 \sqrt{(1 - y^2)}$

Using washer method along the y-axis i.e. integral from 0 to 1.

We have:

$V = 2\pi\int\limits^1_0 {(r_1^2 - r_2^2)} \, dy$

Substitute values for r1 and r2

$V = 2\pi\int\limits^1_0 {(( 2 +2 \sqrt{(1 - y^2)})^2 - ( 2 -2 \sqrt{(1 - y^2)})^2)} \, dy$

Evaluate the squares

$V = 2\pi\int\limits^1_0 {(4 +8 \sqrt{(1 - y^2)} + 4(1 - y^2)) - (4 -8 \sqrt{(1 - y^2)} + 4(1 - y^2))} \, dy$

Remove brackets and collect like terms

$V = 2\pi\int\limits^1_0 {4 - 4 + 8\sqrt{(1 - y^2)} +8 \sqrt{(1 - y^2)}+ 4(1 - y^2) - 4(1 - y^2)} \, dy$

$V = 2\pi\int\limits^1_0 { 16\sqrt{(1 - y^2)} \, dy$

Rewrite as:

$V = 16* 2\pi\int\limits^1_0 {\sqrt{(1 - y^2)} \, dy$

$V = 32\pi\int\limits^1_0 {\sqrt{(1 - y^2)} \, dy$

Using the calculator:

$\int\limits^1_0 {\sqrt{(1 - y^2)} \, dy = \frac{\pi}{4}$

So:

$V = 32\pi\int\limits^1_0 {\sqrt{(1 - y^2)} \, dy$

$V = 32\pi * \frac{\pi}{4}$

$V =\frac{32\pi^2}{4}$

$V =8\pi^2$

Take:

$\pi = 3.142$

$V = 8* 3.142^2$

$V = 78.97731$ --- approximated

3 0

3 years ago

How do you reduce 15/16

alina1380 [7]

Answer:

you can't because they don't have common factors

Step-by-step explanation:

8 0

4 years ago